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2 years ago

2cosx-3=0 cách giải như thế nào

Mathematics

1 answer:

Masteriza [31]2 years ago

7 0

Answer:

Solution does not exist.

Step-by-step explanation:

2cosx-3=0

2cosx=3

cosx=3/2

Solution does not exist.

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Solve the equation<br> -5=y for x.

sesenic [268]

Answer: 5 = y

Step-by-step explanation:

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2 years ago

Tonya’s dog-walking service charges a flat rate of $20 per month, plus $3 per mile that each dog is walked. Beth does not charge

vladimir1956 [14]

Answer:

Ten miles

Step-by-step explanation:

Use this inequality

20 + 3m = 5m

4 0

2 years ago

What is the value of x?

trapecia [35]

3/4 = x / 7.5
4x = 3(7.5)
4x = 22.5
x = 5.625

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2 years ago

Prove the identity (cosx+cosy)^2+(sinx-siny)^2= 2+2cos(x+y)

astra-53 [7]

(cos(x) + cos(y))^2 + (sin(x) - sin(y))^2 Remove the brackets

cos^2(x) + cos^2(y) + 2cos(x)*cos(y) + sin^2(x) - 2(sin(x)*sin(y) + sin^2(y) Combine these two in bold to make 1 because sin^2(x) + cos^2(x) = 1

1 + cos^2(y) + 2cos(x)*cos(y) - 2*sin(x)*cos(y) + sin^2(y)
These two in bold also make 1

2 + 2cos(x)*cos(y) - 2*sin(X)*sin(y) Bring out a common factor of 2
2 +2(cos(x)*cos(y) - sin(x)*sin(y) )

but cos(x+y ) = cos(x)*cos(y) - sin(x)*sin(y)

2 + 2* cos(x + y) is your final answer.

4 0

3 years ago

Read 2 more answers

The students in Suzanne's school are painting a rectangular mural outside the building that will be 15 feet by 45 feet. Scale dr

Katarina [22]

Answer:

The dimensions on paper are 1.992ft by 5.976ft with a scale factor of 7.53

Step-by-step explanation:

The first step will be to find the diagonal of the rea life mural.

We can use Pythagoras' Theorem to do this.

Diagonal = $\sqrt{15^2 +45^2 }$ =47.43 feet.

Now we have the real-life diagonal, we will now relate the diagonal of the painting outside with the one on paper. We can do this by dividing the two diagonals.

This will be 47.43 / 6.3 units = 7.53.

The scale factor is 7.53

To get the dimensions of the length and the breadth on paper, we divide the outside dimensions by the scale factor.

This will be

Length = 15/ 7.53 = 1.992

Breadth = 45/7.53 = 5.976

Therefore, the dimensions on paper are 1.992ft by 5.976ft with a scale factor of 7.53

3 0

3 years ago