A cup slides off a 2.5 m high table with a speed of 2.8 m/s to the right. We can ignore air resistance. What was the cup's horiz ontal displacement during the fall?
1 answer:
Answer:
Horizontal distance = 1.98 m (Approx)
Step-by-step explanation:
Given:
Height = 2.5 m
Speed v = 2.8 m/s
Find:
Horizontal displacement
Computation:
s = ut + (1/2)gt²
2.5 = (1/2)(9.8)t²
t² = 0.5102
t = 0.7079 s
Horizontal distance = (v)(t)
Horizontal distance = (2.8)(0.7079)
Horizontal distance = 1.98 m (Approx)
You might be interested in
The answer is 54 degrees I took the exam I got it right
Answer:
that can help because all you need to remember is that the sum of the angles in a triangle is half of the sum of the angles that add up in a quadrilateral.
Answer:
sadia is 32
Step-by-step explanation:
sadia : father : total
3 6 9
Divide 96 by 9
96/9 = 32/3
Multiply each by 32/3
sadia : father : total
3*32/3 6*32/3 9*32/3
32 64 96
8(1/4)
=(8/1)
=(8)(1)/(1)(4)
=8/4
=2
The answer is
