A cup slides off a 2.5 m high table with a speed of 2.8 m/s to the right. We can ignore air resistance. What was the cup's horiz
ontal displacement during the fall?
1 answer:
Answer:
Horizontal distance = 1.98 m (Approx)
Step-by-step explanation:
Given:
Height = 2.5 m
Speed v = 2.8 m/s
Find:
Horizontal displacement
Computation:
s = ut + (1/2)gt²
2.5 = (1/2)(9.8)t²
t² = 0.5102
t = 0.7079 s
Horizontal distance = (v)(t)
Horizontal distance = (2.8)(0.7079)
Horizontal distance = 1.98 m (Approx)
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Answer:
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Step-by-step explanation:
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Answer:
5x+3=4*-2
5x+3= -8
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