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olga2289 [7]
3 years ago
12

A cup slides off a 2.5 m high table with a speed of 2.8 m/s to the right. We can ignore air resistance. What was the cup's horiz

ontal displacement during the fall?
Mathematics
1 answer:
azamat3 years ago
5 0

Answer:

Horizontal distance = 1.98 m (Approx)

Step-by-step explanation:

Given:

Height = 2.5 m

Speed v = 2.8 m/s

Find:

Horizontal displacement

Computation:

s = ut + (1/2)gt²

2.5 = (1/2)(9.8)t²

t² = 0.5102

t = 0.7079 s

Horizontal distance = (v)(t)

Horizontal distance = (2.8)(0.7079)

Horizontal distance = 1.98 m (Approx)

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What is the fewest number of quarters, nickels, and pennies that can be fairly exchanged for 2 quarters, 6 nickels, and 9 pennie
adoni [48]

Answer:

Your answer is 3 quarters, 2 nickels, and 4 pennies

Step-by-step explanation:

2 quarters plus 6 nickels plus 9 pennies is equal to 89 cents. So if we subtract 75(3 quarters) we get 14 which is less than 25 therefore we must only use nickels and pennies from now on. If we take 14 and subtract 10(2 nickels) we get 4 which less than 5 leaving us only to use pennies, which one a piece so it must be 4 pennies. Hope this helps!

4 0
3 years ago
Construct an explicit rule in function notation for the arithmetic sequence represented in the table. Then determine the value o
strojnjashka [21]

Answer:

After 11 weeks, Darnell′s savings account will have a total of $8,360.

Step-by-step explanation:

The data provided is as follows:

   n:    1        2       3        4

f (n): 260   360   460   560  

Consider the data for f (n).

The series f (n) follows an arithmetic sequence with a common difference of 100 and first term as 260.

The nth term of an arithmetic sequence is:

a_{n}=\frac{n}{2}[2a+(n-1)d]

Compute the value of f (11) as follows:

f(11)=\frac{11}{2}[(2\times260)+(11-1)\times 100]

        =5.5\times[520+1000]\\\\=5.5\times 1520\\\\=8360

Thus, after 11 weeks, Darnell′s savings account will have a total of $8,360.

5 0
3 years ago
Graph the line with the equation y=-1/2x-3
GrogVix [38]
Like this? Brainliest if I got it? :) it’s ok if u don’t

4 0
2 years ago
Please helpppp !!!!!!!!!!! Will mark Brianliest correct answer !!!!!!!!!!!!!!!!!!!
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

This is a duplicate of one I have done for you

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6 0
3 years ago
A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na
ira [324]

Answer:

Approximately 58.2\; \text{nautical miles} (assuming that the bearing is {\rm S$29^{\circ}$W}.)

Step-by-step explanation:

Let v denote the speed of the ship, and let t denote the duration of the trip. The magnitude of the displacement of this ship would be v\, t.

Refer to the diagram attached. The direction {\rm S$29^{\circ}$W} means 29^{\circ} west of south. Thus, start with the south direction and turn towards west (clockwise) by 29^{\circ} to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of v\, t. The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly 29^{\circ}.

Since the hypotenuse is of length v\, t, the dashed line segment opposite to the \theta = 29^{\circ} vertex would have a length of:

\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}.

Substitute in \begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned} and t = 6\; \text{hour}:

\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}.

7 0
2 years ago
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