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Sever21 [200]
3 years ago
7

Sovle the question l-9l + l-1l ​

Mathematics
2 answers:
AlexFokin [52]3 years ago
7 0

the answer is 10 lol  

Tju [1.3M]3 years ago
5 0

Answer:

10

Step-by-step explanation:

The absolute value of -9 is 9

The absolute value of -1 is

9+1=10

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Dina planted a six-foot tree in her backyard which she expects to grow at the rate of 4 feet per year. Find the equation of the
Scrat [10]

Answer:

y = 6 + 4x

After 4 years, the tree would be 22 ft tall.

Step-by-step explanation:

Hi there!

Let x = the number of years that pass

Let y = the height of the tree (ft)

We're given that the 6-foot tree grows at a rate of 4 ft per year. This means that the height of the tree will be equal to 6 ft, the original height, plus another 4 ft every year that passes.

Height of tree = 6 feet + 4 feet × number of years that pass

y = 6 + 4x

To solve for how tall the tree would be 4 years after Dina plants it, replace x with 4, since 4 years have passed:

y = 6 + 4(4)

y = 6 + 16

y = 22

Therefore, the tree would be 22 ft tall.

I hope this helps!

8 0
3 years ago
Need help quick!! <br> WILL GIVE BRAINLIEST
Murljashka [212]

Answer:

3 and 4 x=25, y=29

Step-by-step explanation:

If you need a step by step explanation, I will edit this later.

5 0
3 years ago
Find the slope of the line passing through the points (3,9) and 12,-5)​
astraxan [27]

Answer:

9/-24  or ~ -0.38

Step-by-step explanation:

x       y

3      9

12   -15

from 9 to -15 it will be subtracting 24

From 3 to 12 it will be adding 9

y/x = 9/-24  or -0.375 ~ -0.38

7 0
3 years ago
What should you multiply the top equation by so that y is eliminated when the
VLD [36.1K]
Your answer is D. 2 :)
8 0
3 years ago
Read 2 more answers
What are the roots to<br> the equation<br> 2x² + 6x-1=0?
lys-0071 [83]

Answer:

The roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}    

Step-by-step explanation:

The given quadratic equation is 2 x² + 6 x - 1 = 0

This equation is in form of a x² + b x + c = 0

Let the roots of the equation are ( m , n )

Now , sum of roots = \frac{ - b}{a}

And products of roots = \frac{c}{a}

So, m + n = \frac{ - 6}{2} = - 3

And m × n =  \frac{ - 1}{2}

Or, (m - n)² = (m + n)² - 4mn

Or, (m - n)² = (-3)² - 4 (\frac{ - 1}{2})

Or, (m - n)² = 9 + 2 = 11

I.e m - n = \sqrt{11}

Again m + n = - 3    And m - n = \sqrt{11}

Solving this two equation

(m + n) + ( m - n) = - 3 + \sqrt{11}

I.e 2 m =  - 3 + \sqrt{11}

Or, m = \frac{-3}{2} + \frac{\sqrt{11} }{2}

Similarly n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}      

Hence the roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}      Answer

6 0
3 years ago
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