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3 years ago

Quadrilateral LMNO is a parallelogram, and LM=24-9 and NO=y-2, find the value of "y" and the length of NO.

Mathematics

1 answer:

Slav-nsk [51]3 years ago

7 0

Answer:

y = 7

NO = 5

Step-by-step explanation:

Let the side of the parallelogram LM and NO given be 2y - 9 and y - 2

Since LMNO is a parallelogram, hence;

LM = NO

2y - 9 = y - 2

2y - y = -2 + 9

y = 7

Since NO = y - 2

NO = 7 - 2

NO = 5

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In the right triangle shown, the third side can be represented by the expression

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The third side can be represented by D) $x = \sqrt{z^{2} } -y^{2} .$

Step-by-step explanation:

Step 1:

According to the Pythagorean theorem, the square of the hypotenuse will be equal to the sum of the squares of the other two sides.

In the given triangle, the hypotenuse is the side that is represented by z. Another side on the triangle is represented by the value y.

Step 2:

Assume the other side of the triangle measures x units.

So according to the Pythagorean theorem,

$z^{2} = x^{2} +y^{2} , x^{2} = z^{2} - y^{2} .$

$x = \sqrt{z^{2} } -y^{2}$ which is option D.

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3 years ago

Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n

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Complete Question

Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150

Answer:

Normal sampling distribution can not be used

Step-by-step explanation:

From the question we are told that

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The alternative hypothesis is $H_a : p < 0.015$

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Generally in order to use normal sampling distribution

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$np = 0.015 * 150$

$np = 2.25$

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Step-by-step explanation:

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Step-by-step explanation:

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How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98

Irina18 [472]

Answer:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean for the sample

$\mu$ population mean

$\sigma=1400$ represent the sample standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be $z_{\alpha/2}=2.33$ , replacing into formula (b) we got:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

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3 years ago