Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Answer:
<u>(2) x </u>
<u> 4</u>
Step-by-step explanation:
Given the sqrt(x), x zero
So, given sqrt(x -4), x -4 0
Now solve for x
x - 4 0
x 4
Answer:
your answer would be -13.8y
Answer:
The answer is (3x^2-2x+5)
Answer:
Step-by-step explanation:
1= 2/3
2=5/6
3=21/40
4= 2 11/20
5= 1 1/3
6=5/6
7=1 1/2
8=9/10
9= 5 1/6
10= 2 1/2
