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scZoUnD [109]
3 years ago
13

Shawna needs to buy some pencils and an eraser. She can spend no more than $8. The eraser costs $1 and the pencils cost $0.25 ea

ch. Write an inequality to to find x, the number of pencils Shawna buys.
A) .25x + 1 ≤ 8
B) .25x + 1 < 8
C) .25x + 1 ≥ 8
D) .25x + 1 > 8
Mathematics
1 answer:
madreJ [45]3 years ago
4 0
The correct answer is A
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Solve the equation 9r - 2 = 16 for r.<br> A) 1<br> B) 2<br> C) 4<br> D) 6
yaroslaw [1]
<span>9r - 2 = 16

9r = 16 + 2 

9r = 18

r = 2

Answer : B) 2</span>
6 0
3 years ago
You have 2000 grams of substance A which has decay constant 0.03, and you have 3000 grams of substance B, which has decay consta
joja [24]

Answer:

If you have a quantity X of a substance, with a decay constant r, then the equation that tells you the amount of substance that you have, at a time t, is:

C(t) = X*e^(-r*t)

Now, we know that:

We have 2000g of substance A, and it has a decay constant of 0.03 (i assume that is in 1/year because the question asks in years)

And we have 3000 grams of substance B, with a decay constant of 0.05.

Then the equations for both of them will be:

Ca = 2000g*e^(-0.03*t)

Cb = 3000g*e^(-0.05*t)

Where t is in years.

We want to find the value of t such that Ca = Cb.

So we need to solve:

2000g*e^(-0.03*t) = 3000g*e^(-0.05*t)

e^(-0.03*t) = (3/2)e^(-0.05*t)

e^(-0.03*t)/e^(-0.05*t) = 3/2

e^(t*(0.05 - 0.03))  = 3/2

e^(t*0.02) = 3/2

Now we can apply Ln(x) to both sides, and get:

Ln(e^(t*0.02)) = Ln(3/2)

t*0.02 = Ln(3/2)

t = Ln(3/2)/0.02 = 20.3

Then after 20.3 years, both substances will have the same mass.

6 0
3 years ago
Please need help thank
Svetlanka [38]
183.75 because if you did $1470 then divided it by 8 it would =183.75
6 0
3 years ago
A grocer wanted to mix 19 liters milk of $2.2 with 1 kg cacao to make a mixture of hot chocolate. What should be the cost of mil
Ad libitum [116K]

Answer:

for this, I'm going to assume that the cacao powder costed $2.2. If the cacao costs $2.2 then the milk will cost $0.8.

Step-by-step explanation:

If you subtract 2.2 from 3 then you get 0.8. Also if you add 2.2 with 0.8 then you get 3. another way to simplify it is to add one zero on the end, like this 22+8=30.

4 0
3 years ago
If m(x)=x+5/x-1 and n(x)=x-3 which function has the same domain as (m•n)(x)
worty [1.4K]
Consider the functions m and n:


i) m(x)=\frac{x+5}{x-1}   for x≠1.

the domain of m is  all the real numbers except 1.


ii) n(x)=x-3 is a polynomial function, because x-3 is a linear polynomial. 

The domain of any polynomial function is all real numbers. To determine the Range of this function, let c be a value in the range:

x-3=c, then x=3+c.

so if we want the function to produce c, we just set x=3+c, check:

n(3+c)=(3+c)-3=c.

This means that the Range of n is all real numbers.


What this means, is that the input (x) of the function n(x) can be any real number, and the output (n(x)) can also be any number.

so let n(x)=a, consider m(a):

m(a)=(a+5)/(a-1), clearly a≠1, this means n(x)=x-3≠1, that is x≠-4
 

This means that the domain of the composed function, m(n(x)) =  say f(x), 

is all Real numbers except 4.


Check: letting x be 4, would mean n(4)=4-3=1

which would mean m(n(4))=m(1)=(1+5)/(1-1)=6/0, which makes no sense.


Answer: Any function with domain R-{4}, has the same domain of (mon)(x) 

6 0
3 years ago
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