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allsm [11]
3 years ago
11

Differentiate with product rule​

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0

Answer:

{ \boxed{ \bf{ \frac{dy}{dx} = v \frac{du}{dx}  + u \frac{dv}{dx}  }}}

u = ( x + 1 )

v = ( 2x + 5 )²

{ \tt{ \frac{dy}{dx}  =  {(2x + 5) {}^{4} .(1) + (x + 1).(2)(2x + 5) {}^{3} } }} \\ =  { \tt{ {(2x + 5)}^{3} ((2x + 5) +(2x + 2) }} \\  = { \tt{ \frac{dy}{dx} =  {(2x + 5)}^{3}(4x + 7)  }}

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