Answer:
756
Step-by-step explanation:
The ratio of areas is the square of the scale factor.
First, we find the scale factor from the blue solid to the red solid.
scale factor = 6/4 = 3/2
The ratio of areas is the square of the scale factor:
ratio of areas = (3/2)^2 = 9/4
volume of red solid = volume of blue solid * ratio of areas
volume of red solid = 336 m^2 * 9/4 = 756 m^2
Answer: S = 756 m^2
Answer:
titutex=cos\alp,\alp∈[0:;π]
\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+
1−x
2
∣=
2
(2x
2
−1)\Leftright∣cos\alp+sin\alp∣=
2
(2cos
2
\alp−1)
\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N
2
cos(\alp−
4
π
)∣=N
2
cos(2\alp)\Right\alp∈[0;
4
π
]∪[
4
3π
;π]
1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;
4
π
]
\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−
4
π
)=cos(2\alp)…
2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[
4
3π
;π]
\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−
4
π
)=cos(2\alp)…
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Graph will look like this if this is one of the options
3y - 1 < 3
Isolate the y. Treat the less than or equal like an equal sign.
Do the opposite of PEMDAS. First, add 1 to both sides
3y - 1 (+1) < 3 (+1)
3y < 4
Next, divide 3 from both sides
3y/3 < 4/3
y < 4/3
y < 4/3 is your answer
hope this helps
