Question

Can you help me with my work

Answer 1

Number one is x=9,-9
number two is x=0
number three is x=12,-12
number four is 5i, -5i

Answer 2

For this case we have:

Question 1:

We want to know the solution of$x ^ 2-81 = 0$

Adding 81 to both sides of the quadratic equation we have:

$x ^ 2-81 + 81 = 81\\x ^ 2 = 81$

Applying square root on both sides of the equation:

$\sqrt {x ^ 2} = \pm \sqrt {81}\\x = \pm 9$

So, we have two solutions:

$x_ {1} = + 9\\x_ {2} = - 9$

Answer:

$x_ {1} = + 9\\x_ {2} = - 9$

Question 2:

In this case, we want to solve the following quadratic equation:

$2x ^ 2-26 = 0$

Adding 26 to both sides of the quadratic equation we have:

$2x ^ 2-26 + 26 = 26\\2x ^ 2 = 26$

Dividing between 2 on both sides of the equation:

$\frac {2x ^ 2} {2} = \frac {26} {2}\\x ^ 2 = 13$

Applying square root on both sides of the equation:

$\sqrt {x ^ 2} = \pm \sqrt {13}$

$x = \pm \sqrt {13}$

So, we have two solutions:

$x_ {1} = + \sqrt {13}\\x_ {2} = - \sqrt {13}$

Answer:

$x_ {1} = + \sqrt {13}\\x_ {2} = - \sqrt {13}$

Question 3:

For this case, we have a quadratic function of the form $y = f (x)$, where $f (x) = x ^ 2-144$. They ask us to find the roots. So:

$x ^ 2-144 = 0$

Adding 144 to both sides of the quadratic equation we have:

$x ^ 2-144 + 144 = 144\\x ^ 2 = 144$

Applying square root on both sides of the equation:

$\sqrt {x ^ 2} = \pm \sqrt {144}\\x = \pm 12$

So, we have two solutions:

$x_ {1} = + 12\\x_ {2} = - 12$

Answer:

$x_ {1} = + 12\\x_ {2} = - 12$

Question 4:

For this case we have a quadratic function of the form $y = f (x)$, where $f (x) = x ^ 2 + 25$

Antoine says he has no solution. We must verify:

$x ^ 2 + 25 = 0$

Subtracting 25 from both sides of the equation:

$x ^ 2 + 25-25 = -25\\x ^ 2 = -25$

Applying square root on both sides of the equation:

$\sqrt {x ^ 2} = \pm \sqrt {-25}$

By definition:

$i = \sqrt {-1}\\i ^ 2 = -1$

So:

$x = \pm \sqrt {25i ^ 2}\\x = \pm5i$

So, we have two solutions:

$x_ {1} = + 5i\\x_ {2} = - 5i$

Answer:

$x_ {1} = + 5i\\x_ {2} = - 5i$