What are the solutions of 8x2 = 6 + 22x? Check all of the boxes that apply.

Mathematics

2 answers:

Ne4ueva [31]2 years ago

7 0

Answer:

x = 3 x = ‐1/4

Step-by-step explanation:

the first one is also right!!

Tamiku [17]2 years ago

6 0

Answer:

x = 3 x = ‐1/4

Step-by-step explanation:

Was right on the quiz

You might be interested in

Which of the following points is in the solution set of y > -x2 + 5?

Stella [2.4K]

Its the third option (2, 4)

7 0

2 years ago

Read 2 more answers

the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years

Yuliya22 [10]

Answer: 125 g

<u>Step-by-step explanation:</u>

$A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k$

$\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125$

8 0

3 years ago

Use the image below and find the missing angles

Colt1911 [192]

Step-by-step explanation:

w = 34° (alternate interior angles)

x = 34° (vertically opposite angles)

y = 101°

z = 79° (corresponding angles)

7 0

2 years ago

There are 100 students at a college who have taken a course in calculus, 110 who have taken a course in discrete mathematics, an

vesna_86 [32]

Answer:

110 students

Step-by-step explanation:

The number of students who have only taken calculus is given by the number of students who have taken calculus minus the students who have taken both classes:

$C =100 -50\\C= 50\ students$

The number of students who have only taken discrete mathematics given by the number of students who have taken discrete mathematics minus the students who have taken both classes:

$D =110 -50\\C= 60\ students$