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lapo4ka [179]
3 years ago
8

The square root of -1 is:

Mathematics
1 answer:
Sliva [168]3 years ago
4 0
The square root of -1 is I
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Solve for x and y<br><br> x-y=11<br><br> 2x+y=19
Ilia_Sergeevich [38]
X=10 y=-1
U can use Photomath for questions like this
7 0
3 years ago
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topjm [15]

Step-by-step explanation:

I'm not sure but I think there are 2 terms!

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3 years ago
The tables represent two linear functions in a system.<br><br> What is the solution to this system?
Darya [45]

The solution to this system is (x, y) = (8, -22).

The y-values get closer together by 2 units for each 2-unit increase in x. The difference at x=2 is 6, so we expect the difference in y-values to be zero when we increase x by 6 (from 2 to 8).

You can extend each table after the same pattern.

In table 1, x-values increase by 2 and y-values decrease by 8.

In table 2, x-values increase by 2 and y-values decrease by 6.

The attachment shows the tables extended to x=10. We note that the y-values are the same (-22) for x=8 (as we predicted above). That means the solution is ...

... (x, y) = (8, -22)

8 0
3 years ago
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Find the equation of the line parallel to y=6 that contains the point (-1,1). Write the equation in slope intercept form
julia-pushkina [17]

Given:

The equation of parallel line is y=6.

The line contains the point (-1,1).

To find:

The equation of the line.

Solution:

The slope intercept form of a line is:

y=mx+b

Where, m is the slope and b is the y-intercept.

The equation of parallel line is

y=6

It can be written as

y=(0)x+6

The slope of this line is 0.

The slopes of two parallel lines are always equal. So, the slope of the required line is also 0. It passes through the point (-1,1) so the equation of the line is:

y-y_1=m(x-x_1)

y-1=0(x-(-1))

y-1=0

y=1

Therefore, the equation of the required line is 1.

7 0
3 years ago
Write an expression as a monomial in a standard form:<br> −5x^3·y^2·5x^2·y^3
borishaifa [10]

Answer:

-25x⁵y⁵

Step-by-step explanation:

Coefficients include (-5)(5) = -25

x-factors include (x^3)(x^2) = x^5

y-factors include (y^2)(y^3) = y^5

Then the product is ...

... -25x^5·y^5

4 0
4 years ago
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