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2 years ago

(4n + 14) + (5 + 8n)

Mathematics

1 answer:

Sonbull [250]2 years ago

4 0

Answer:

12n+19

Step-by-step explanation:

(4n + 14) + (5 + 8n)

4n+14+5+8n

12n+19

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A corporate team-building event costs $13, plus an additional $6 per attendee. How many

andrew-mc [135]

Answer:

Step-by-step explanation:

The cost for n attendees will be ...

cost = 2 + 2n

We want the cost to be, at most, 26, so we have ...

26 ≥ 2 +2n

Dividing by 2 gives ...

13 ≥ 1 + n

And subtracting 1, we find the answer:

12 ≥ n

At most, there can be 12 attendees.

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3 years ago

Someone please help me will give BRAILIEST!!!!!!!!

Bogdan [553]

5/6
is the answer because you could roll anything other than a four

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3 years ago

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Consider the graph of the linear function h(x) = –6 + x. Which quadrant will the graph not go through and why?

Lesechka [4]

H ( x ) = - 6 + x
m = 1 ( the slope )
b = - 6 ( y - intercept )
x - intercept:
0 = - 6 + x
x = 6
The graph is going through Quadrants: I, II and IV.
Answer:
B ) Quadrant II, because the slope is positive and y-intercept is negative.

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3 years ago

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NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

2 years ago

Can some one answer this ?

earnstyle [38]

This is your answer

5 0

3 years ago