H ( x ) = - 6 + x m = 1 ( the slope ) b = - 6 ( y - intercept ) x - intercept: 0 = - 6 + x x = 6 The graph is going through Quadrants: I, II and IV. Answer: B ) Quadrant II, because the slope is positive and y-intercept is negative.
If we look at the function, we realize that it is a linear one. It can also be expressed in the form h(x) = x - 6 For simplicity. Upon entering x = 0 to find the y-intercept (since we know that the value of x on the y intercept is 0) we see that the y-intercept is -6; thus, negative. Next, we check the sign of the coefficient of x (which is 1 in this case) and we see that the slope is positive. Thus, when we make a quick sketch or imagine the graph, we see that the line will not pass through the second quadrant. The answer is B.
