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mojhsa [17]
3 years ago
6

Question 6 (5 points)

Mathematics
1 answer:
AleksAgata [21]3 years ago
5 0

Answer:

(26,-2)

Step-by-step explanation:

For any two points on coordinate plane (x1,y1) and ( x2,y2)

coordinate of midpoint is given by (x1+x2)/2 , (y1+y2)/2

Given

(x1,y1) = (-4,-8)

midpoint : (11,-5)

let other point be x2 and y2

therefor by using formula for midpoint coordinate given above we have

midpoint : (11,-5) = (-4+x2)/2 , (-8+y2)/2

Hence point

11 will be equivalent to (-4+x2)/2

11 = (-4+x2)/2

=> 11*2 = -4+x2

=>22 + 4 = x2

=>x2 = 26

similarly

-5 will be equal to (-8+y2)/2

-5 = (-8+y2)/2

=> -5*2 = -8+y2

=> -10 + 8 = y2

=> y2 = -2

Therefore coordinates of other point is  (26,-2).

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Find the estimates of x^2-x-2=3
Julli [10]

Answer:

x=\frac{1+\sqrt{21}}{2}\approx 2.79\\or\ x=\frac{1-\sqrt{21}}{2}\approx -1.79

Step-by-step explanation:

Given

Quadratic equation is

x^2-x-2=3\\x^2-x-5=0

Roots of the quadratic equation ax^2+bx+c=0 are

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\

So, for the given equation roots are

x=\frac{1\pm\sqrt{(-1)^2-4(1)(-5)}}{2\cdot 1}\\x=\frac{1\pm\sqrt{21}}{2}\\so, x=\frac{1+\sqrt{21}}{2}\approx 2.79\\or\ x=\frac{1-\sqrt{21}}{2}\approx -1.79

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Step-by-step explanation:

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Henry has a bag containing 39 letter tiles, some consonants, and some vowels. He selects a tile without looking and then replace
adoni [48]

Answer:

21 consonant tiles

Step-by-step explanation:

Henry has a bag containing 39 letter tiles, some consonants, and some vowels.

He selects a tile without looking and then replaces it. If he pulls 7 consonant tiles and 6 vowel tiles, which is the most likely number of consonant tiles in Henry's bag?

Step 1

We add up the number of tiles that he pulls out of the bag

= 7 consonant tiles + 6 vowel tiles

= 13 tiles

Step 2

We divide the total number of tiles in the bag by the total number of tiles that was pulled out of the bag

= 39 tiles ÷ 13 tiles

= 3

Step 3

The most likely number of consonant tiles in Henry's bag is calculated as:

3 × The number of consonant tiles that was pulled out of the bag.

Hence:

3 × 7 consonant tiles

= 21 consonant tiles.

Therefore, the most likely number of consonant tiles in Henry's bag is 21 consonant tiles.

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