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Nastasia [14]
3 years ago
8

GUYS I REALLY NEED HELP I DON'T UNDERSTAND :"(

Mathematics
1 answer:
ANTONII [103]3 years ago
4 0

Answer:

the answer is 7

Step-by-step explanation:

plot the points then count how many spaces there are going diagnal

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Please soleeeeeeeeeeeeèeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee​
sineoko [7]

Step-by-step explanation:

Answer is 99. I am pretty sure.

8 0
3 years ago
PLEASE HELP!! (Give reasonable answer)
gladu [14]

Answer: B

Step-by-step explanation: You just multiplying 25 with 10 and w which can be simplified as 24(w+10) and adding with the 13.5 x 10 and 13.5 x w, which can be simplified as 13.5(10+w)

7 0
2 years ago
Porky the pig weighs 1,125 lbs. Less than Kobe the Cow. After each gains 50lbs. Kobe the Cow will weigh ten times as much as por
Papessa [141]

Answer:

Step-by-step explanation:

Let x represent the initial weight of Porky the pig.

Porky the pig weighs 1,125 lbs less than Kobe the Cow. This means that the initial weight of Kobe the cow is

x + 1125

After each gains 50lbs. Kobe the Cow will weigh ten times as much as porky the pig. This means that

(x + 1125) + 50 = 10(x + 50)

x + 1125 + 50 = 10x + 500

10x - x = 1125 + 50 - 500

9x = 675

x = 675/9

x = 75

Porky's current weight is

75 + 50 = 125 lbs

Kobe's current weight is

(75 + 1125) + 50

= 1250 lbs

4 0
3 years ago
Suppose you pay $1.00 to roll a fair die with the understanding you will get $3.00 back rolling a 4 or a 2, and nothing otherwis
nikdorinn [45]

There are 2 chances out of 6 to win $3

Every 6 rolls you are expected to win $6

Every 3 rolls you are expected to win $3.

On average, even though it's impossible, every roll you would make $1.

6 0
2 years ago
The capacity of an elevator is 12 people or 2088 pounds. the capacity will be exceeded if 12 people have weights with a mean gre
boyakko [2]

suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.

Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?

Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.

Mean = 177

standard deviation = 26

We find z-score using given mean and standard deviation

z = \frac{x-mean}{standard deviation}

= \frac{174-177}{26}

=-0.11538

Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)

= 0.5438

P(weight will be greater than 174 lb) = 0.5438

8 0
3 years ago
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