1/X+4 = 5 it is solving rational equations

sammy [17]

Well i believe its 23 my son

5 0

3 years ago

Olivia kicks a soccer ball from the ground with an initial vertical velocity of 15 m/s. Which equation can be used to find the t

babunello [35]

Answer:

The answer is below

Step-by-step explanation:

Motion shows the change in the position of an object over time. This change is showed in terms of displacement, distance, velocity, acceleration, time and speed. The equations of motion shows this relationship.

Since the soccer ball is kicked up with an initial velocity (u) of 15 m/s, the acceleration due to gravity (g) acts on the ball. If the ball is kicked at an angle Θ, the time t it takes for the ball to reach the ground is:

$t=\frac{2u*sin(\theta)}{g} \\\\t=\frac{2(15)*sin(\theta)}{g} \\\\t=\frac{30*sin(\theta)}{g} \\\\If\ it\ is\ kicked\ vertical\ then\ \theta=90^0,hence:\\\\t=\frac{30*sin(90)}{g}= \frac{30}{g }$

7 0

3 years ago

In the diagram below, OPis circumscribed about quadrilateral ABCD. What is<br> the value of x?

Nikitich [7]

9514 1404 393

Answer:

C. 82

Step-by-step explanation:

Opposite angles of an inscribed quadrilateral are supplementary. So ...

(x + 10°) + 88° = 180°

x = 180° -98°

x = 82°

7 0

3 years ago

What is 4/15 as a decimal and percent?

mamaluj [8]

4/15 is a repeating decimal.
Decimal- 0.2666...
Percent- 26.66...%
Rounded Decimal- 0.267
Rounded Percent- 26.67%

3 0

4 years ago

Use the Statistical Applet: P ‑Value for a Test of One Proportion to answer the question.You have taken a sample of ????=1000 in

umka21 [38]

Answer:

$z=\frac{0.785 -0.7}{\sqrt{\frac{0.7(1-0.7)}{750}}}=5.08$

$p_v =P(z>5.08)=1.88x10^{-7}$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is highr than 0.67 or 67% .

Step-by-step explanation:

1) Data given and notation

n=20 represent the random sample taken

X=15 represent the people who eat breakfast

$\hat p=\frac{15}{20}=0.75$ estimated proportion of people who eat breakfast

$p_o=0.67$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 67%:

Null hypothesis: $p\leq 0.67$

Alternative hypothesis: $p > 0.67$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.785 -0.7}{\sqrt{\frac{0.7(1-0.7)}{750}}}=5.08$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>5.08)=1.88x10^{-7}$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is highr than 0.67 or 67% .

6 0

3 years ago