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3 years ago

Huh?6(2 + 4) - 1_________2 x 3 + 1

Mathematics

1 answer:

a_sh-v [17]3 years ago

4 0

Answer:

equaul

Step-by-step explanation:

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Which expression is the simplest form of..

S_A_V [24]

Answer: Answer choice: [A]: " x⁻ ⁴ " .

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Step-by-step explanation:

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Given:

{x ^ $^( {\frac{-4}{7}) }^7$ ;

→ Simplify.

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Note the following property of exponents:

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→ (xᵃ) ᵇ = x ⁽ ᵃ * ᵇ ⁾ ; {a ≠ 0 ; b ≠ 0 .} .

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As such:

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→ {x ^ $^( {\frac{-4}{7}) }^7$ ;

= x ^ ( $[(\frac{-4}{7}) * 7 ]$ ;

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Find: $[(\frac{-4}{7}) * 7 ] ; Note: " 7 = [tex]\frac{7}{1}$ " .

So: Find: " $[(\frac{-4}{7} * [tex]\frac{7}{1}$ " ;

The 2 (two) "7 's " ; cancel out to "1" ;

→ {since: " 7 ÷ 7 = 1 " } ;

And we have:

-4 * 1 = -4 .

So, we have:

" x ⁻ ⁴ " ; which is: Answer choice: [A]: " x⁻ ⁴ " .

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Choice: [C} — is also an equivalent; however, the question asks for the "simplest form" — which is: Answer choice: [A].

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3 years ago

Which is the addend and the sum?

snow_tiger [21]

For that problem, all you have to do is add all of the trees up together. :3

8 0

3 years ago

Read 2 more answers

5. What is the principal square root of -25?<br> -5 <br>No Real Number <br>5<br>1/5

wlad13 [49]

Answer:

no real number

Step-by-step explanation:

no square root of neg. num.

if my anwser helps please mark as brainliest.

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3 years ago

Question: Michelle is making goodie bags for Christmas filled with chocolate and candy. Chocolates cost $2.50 per lb and candy c

ehidna [41]

The answer will be 80

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3 years ago

Match each equation on the left with the number and type of its solutions on the right.

klemol [59]

Answer:

Step-by-step explanation:

1). Given equation is,

2x² - 3x = 6

2x² - 3x - 6 = 0

To find the solutions of the equation we will use quadratic formula,

x = $\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Substitute the values of a, b and c in the formula,

a = 2, b = -3 and c = -6

x = $\frac{3\pm\sqrt{(-3)^2-4(2)(-6)}}{2(2)}$

x = $\frac{3\pm\sqrt{9+48}}{4}$

x = $\frac{3\pm\sqrt{57}}{4}$

x = $\frac{3+\sqrt{57}}{4},\frac{3-\sqrt{57}}{4}$

Therefore, there are two real solutions.

2). Given equation is,

x² + 1 = 2x

x² - 2x + 1 = 0

(x - 1)² = 0

x = 1

Therefore, there is one real solution of the equation.

3). 2x² + 3x + 2 = 0

By applying quadratic formula,

x = $\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

x = $\frac{-3\pm\sqrt{3^2-4(2)(2)}}{2(2)}$

x = $\frac{-3\pm\sqrt{9-16}}{4}$

x = $\frac{-3\pm i\sqrt{7}}{4}$

x = $\frac{-3+ i\sqrt{7}}{4},\frac{-3- i\sqrt{7}}{4}$

Therefore, there are two complex (non real) solutions.

3 0

3 years ago

Huh?6(2 + 4) - 1_________2 x 3 + 1​

Huh?6(2 + 4) - 1_________2 x 3 + 1