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labwork [276]
3 years ago
9

Louis wants to carpet the rectangular floor of his basement. The basement has an area of 1,176 square feet. The width of the bas

ement is 2 3 its length. What is the length of Louis's basement?
Mathematics
1 answer:
julia-pushkina [17]3 years ago
6 0

Answer: 42 feet

Step-by-step explanation:

Let the length be x

Therefore, width = 2/3x

Area = Length × Width

Therefore, x × 2/3x = 1176

2/3x² = 1176

Divide both side by 2/3

x² = 1176 ÷ 2/3

x² = 1176 × 3/2

x² = 1764

x = ✓1764

x = 42

The length is 42 feet

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(6x2 + x - 3)(2x2 +1)
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Step-by-step explanation: I'm not sue if the x's are squared so i didn't squared them but i got : 23x³-6x²

+13x-3

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3 years ago
Select the type of equations. <br><br> A)consistent <br> B)equivalent<br> C) inconsistent
Andreyy89
A and c.. equivalent is not an equation i dont think
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Find the range of the function for the given domain: f(x)=2x^2−7 with domain: x = {-4, -2, 0, 3}
-BARSIC- [3]

Answer:

f(x)=2(-4)^2-7

=-8^2-7

= 64-7

=57

7 0
3 years ago
The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial
qaws [65]

Answer:

Step-by-step explanation:

Let P be the population of the community

So the population of a community increase at a rate proportional to the number of people present at a time

That is

\frac{dp}{dt} \propto p\\\\\frac{dp}{dt} =kp\\\\ [k \texttt {is constant}]\\\\\frac{dp}{dt} -kp =0

Solve this equation we get

p(t)=p_0e^{kt}---(1)

where p is the present population

p₀ is the initial population

If the  initial population as doubled in 5 years

that is time t = 5 years

We get

2p_o=p_oe^{5k}\\\\e^{5k}=2

Apply In on both side to get

Ine^{5k}=In2\\\\5k=In2\\\\k=\frac{In2}{5} \\\\\therefore k=\frac{In2}{5}

Substitute k=\frac{In2}{5}  in p(t)=p_oe^{kt} to get

\large \boxed {p(t)=p_oe^{\frac{In2}{5}t }}

Given that population of a community is 9000 at 3 years

substitute t = 3 in {p(t)=p_oe^{\frac{In2}{5}t }}

p(3)=p_oe^{3 (\frac{In2}{5}) }\\\\9000=p_oe^{3 (\frac{In2}{5}) }\\\\p_o=\frac{9000}{e^{3(\frac{In2}{5} )}} \\\\=5937.8

<h3>Therefore, the initial population is 5937.8</h3>
7 0
3 years ago
Find the product of ( 2a2– 3b2) and ( a +b2- 3z)​
Bond [772]

Answer:

2a^3+2a^2b^2-6a^2z-3ab^2-3b^4+9b^2z

Step-by-step explanation:

(2a^2-3b^2)(a+b^2-3z)

Start by distributing the 2a^2 into all of the terms in between the second parentheses.

2a^3+2a^2b^2-6a^2z

Next, distribute the -3b^2 into all of the terms in between the second parentheses.

-3ab^2-3b^4+9b^2z

For the sake of simpler interpretation, I separated the two above, but they are together:

2a^3+2a^2b^2-6a^2z-3ab^2-3b^4+9b^2z

Since the terms are already in descending order, we do not need to rearrange them.

4 0
3 years ago
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