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Zepler [3.9K]
3 years ago
5

A projectile was fired horizontally from a cliff 20m above the ground. If

Physics
1 answer:
Montano1993 [528]3 years ago
8 0

The initial velocity of the projectile is 19.8m/s

Explanation:

First, find time.

From our kinematics equations:

delta y = Vi•t + (1/2)at^2

rearrange,

t = sqrt[(2•delta y)/a]

t = sqrt[(2•20m)/9.8m/s^2]

t = 2.02s

Next, plug time into new kinematics equation to solve for the Vi in the x direction (horizontal)

delta x = Vi•t + (1/2)at^2

delta x = Vi•t

Rearrange:

Vi = delta x/t

Vi = 40m/2.02s

Vix = 19.8m/s

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7.5 volts

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3 years ago
A small particle has charge -2.00 uC and mass 1.50×10-4 kg. It moves from point A, where the electric potential is V(A) = 200 V,
Svet_ta [14]

Answer:

v_b=6.13 m/s..

Explanation:

Since no external force is acting on the system.

Therefore, Total energy remains constant before and after.

So, Total energy of system= energy due to potential applied+kinetic energy

T.E=qV_a+\dfrac{1}{2}mv_a^2=qV_b+\dfrac{1}{2}mv_b^2\\\dfrac{1}{2}mv_b^2=\dfrac{1}{2}mv_a^2+q(V_a-V_b)\\

(Here v=velocity ,V=potential ,q=charge and m=mass).

Putting values .

We get,  v_b=6.13 m/s..

At point B charged particle is moving faster as compared to point A.

Hence, it is the required solution.

5 0
4 years ago
You are unloading a refrigerator from a delivery van. The ramp on the van is 5.0 mm long, and its top end is 1.4 mm above the gr
Ivahew [28]

Answer:

Work done is 1.31 J.

Explanation:

Given:

Length of the ramp (L) = 5.0 mm

Height of the top end (H) = 1.4 mm

Horizontal force applied (F) = 270 N

Work done (W) = ?

We know that,

Work done is equal to the product of force and displacement caused along the line of application of force.

Here, the force acting on the refrigerator is in the horizontal direction while the refrigerator is moving down along the length of the ramp. So, we have to first find the horizontal component of the displacement caused.

Now, consider the triangle ABC representing the given situation. The point A is the top end point of the ramp, AB is the length of the ramp, AC is the vertical displacement of the refrigerator and BC is the horizontal displacement of the refrigerator.

Using Pythagoras theorem,

AB^2=BC^2+AC^2\\\\(5.0)^2=BC^2+(1.4)^2\\\\BC=\sqrt{25.0-1.96}\\\\BC=4.86\ mm

Now, force applied on the refrigerator is in the direction opposite to the horizontal component of displacement. So, work is negative.

Work = Force × Horizontal displacement

W=270\ N\times 4.86\ mm\\\\W=1312.2\ \textrm{N-mm}\\\\W=1.31\ J\ \ \ \ \ \textrm{ [1 mm = 0.001 m]}

Therefore, work done is 1.31 J.

7 0
3 years ago
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