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mixas84 [53]
3 years ago
6

What happens when you place two magnets close together.​

Physics
1 answer:
wlad13 [49]3 years ago
3 0
They attract and stick together
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A "sound" is different than a "sound wave"
e-lub [12.9K]

Answer:

sound is how an animal or human perceives a sound wave

5 0
2 years ago
A soccer player kicks a soccer ball at +10.0 m/s at an angle of 60°. What are the horizontal and vertical components of velocity
Nastasia [14]
This seems like a calculus problem. I'm assuming you would use cos and sin. so here's the vertical component +10.0m/s multiplied by sin60 = 8.66 rounded to the hundreths place. Now for horizontal, that would be +10.0m/s multiplied by cos60 = 5. hope this helped.
3 0
3 years ago
Read 2 more answers
Was the cannonball able to hit its target of 50 meters when the initial velocity was 20 m/s? Why?/Why Not?
frosja888 [35]

Answer:

The cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.

Explanation:

From the question given above, the following data were obtained:

Height to which the target is located = 50 m

Initial velocity (u) = 20 m/s

To know whether or not the cannon ball is able to hit the target, we shall determine the maximum height to which the cannon ball attained. This can be obtained as follow:

Initial velocity (u) = 20 m/s

Final velocity (v) = 0 (at maximum height)

Acceleration due to gravity (g) = 10 m/s²

Maximum height (h) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = 20² – (2 × 10 × h)

0 = 400 – 20h

Collect like terms

0 – 400 = – 20h

– 400 = – 20h

Divide both side by – 20

h = – 400 / – 20

h = 20 m

Thus, the the maximum height to which the cannon ball attained is 20 m.

From the calculations made above, we can conclude that the cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.

3 0
3 years ago
Consider a particle on which several forces act, one of which is known to be constant in time: Fi = 3.00 i +4.00 ) N. As a resul
Leviafan [203]

Given that.

F=3•i+4•j

And it from point (0,0)m to (5,6)m

dx=final position - initial position

dx=(5,6)-(0,0)

dx=(5,6)m

dx=5•i +6•j

Work done by the force is give by

W = F•dx

W=F•dx

Note that i•i=j•j=1 and i•j=j•i=0

Then,

W=(3i+4j)•(5i+6j)

Therefore,

W=3i•(5i+6j)+4j•(5i+6j)

W=15i•i+18i•j+20j•i+24j•j

W=15+0+0+24

W=39J

Then the work done by the force is 39 Joules

4 0
3 years ago
A patricle is accelerated uniformly from rest, so that after 10 seconds it has a speed of 15m/s find its acceleration and the di
grin007 [14]

Answer:

Its acceleration is 1.5 \frac{m}{s^{2} } and the distance it has covered is 150 m.

Explanation:

Acceleration is a quantity that indicates the variation in speed of a moving body as time passes. That is, acceleration relates changes in velocity with the time in which they occur.

The average acceleration is defined as the relationship between the variation or change in the speed of a mobile and the time used in said change:

acceleration=\frac{change in speed}{time}

In this case:

  • change in speed= final speed - initial speed= 15 m/s - 0 m/s= 15 m/s
  • time= 10 s

Replacing:

acceleration=\frac{15 \frac{m}{s} }{10 s}

and solving you get:

<u><em>acceleration= 1.5 </em></u>\frac{m}{s^{2} }<u><em></em></u>

Speed ​​is a quantity that expresses the relationship between the space traveled by an object and the time used for it. This is:

speed=\frac{distance}{time}

So the distance can be calculated as:

distance= speed* time

In this case:

  • speed= 15 m/s
  • time= 10 s

Replacing:

distance= 15 m/s* 10 s

and solving you get:

<u><em>distance= 150 m</em></u>

<u><em>Its acceleration is 1.5 </em></u>\frac{m}{s^{2} }<u><em> and the distance it has covered is 150 m.</em></u>

8 0
3 years ago
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