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Finger [1]
3 years ago
12

Calculate the volume of this regular solid. A cylinder labeled B at the top, 13 centimeters high with a radius of 4 centimeters.

What is the volume of the cylinder? Round your answer to the nearest hundredth.
Physics
2 answers:
geniusboy [140]3 years ago
6 0

Answer:

653.45 is the answer

Explanation:

Kryger [21]3 years ago
4 0

Answer:

The volume of the cylinder is 653.71\ \text{cm}^3

Explanation:

Given that,

The height of the cylinder is 13 cm

Radius of the cylinder is 4 cm

We need to find the volume of the cylinder. The formula that is used to find the volume of a cylinder is given by :

V=\pi r^2 h\\\\V=\dfrac{22}{7} \times (4)^2 \times 13\\\\V=653.71\ \text{cm}^3

So, the volume of the cylinder is 653.71\ \text{cm}^3

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What environmental factor does the pyramid of energy incorporate that prevents it from inverting?
Brilliant_brown [7]

The environmental factor that the pyramid of energy incorporates that prevents it from inverting is population size.

 

Population size<span> <span>is the actual number of individuals in a </span>population. Populationdensity is a measurement of population size<span> per unit area, i.e., </span>population sizedivided by total land area. Abundance refers to the relative representation of a species in a particular ecosystem.</span>

 

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

5 0
3 years ago
Read 2 more answers
If the weight of the ruler is one Newton ,Gc cannot have a value more than 25cm
nevsk [136]

If the length of the ruler is 50 cm, the center of gravity cannot be greater than 25 cm.

The given parameters:

  • Weight of the ruler = 1 N

<h3>What is center of gravity (CG)?</h3>
  • Center of gravity is the point at which the weight of an object is concentrated.

Let the length of the ruler = L

The center of the gravity of the ruler is calculated as follows;

X_{CG} = \frac{W(L_0) + W(L -X_{CG})}{W} \\\\X_{CG} = \frac{1(0) + 1(L -X_{CG})}{1}\\\\X_{CG} = L - X_{CG}\\\\X_{CG } + X_{CG} = L\\\\2X_{CG} = L\\\\X_{CG} = \frac{L}{2} \\\\when , \ L = 50 \ cm\\\\X_{CG} = \frac{50}{2} \\\\X_{CG} = 25 \ cm

Thus, if the length of the ruler is 50 cm, the center of gravity cannot be greater than 25 cm. This may change if the length of the ruler changes because the center of gravity of uniform ruler depends on the length of the ruler.

Learn more about center of gravity here: brainly.com/question/6765179

4 0
2 years ago
When a resistor is connected to a 12 volt source, it draws a 185 mA current. what's the resistance? (I said 65 ohms). the same r
lyudmila [28]

Resistance-1 = (voltage-1) / (current-1) =

                       (12 V)  /  (0.185 A)  =  64.9 ohms .

Resistance-2 = (voltage-2) / (current-2) =
 
                           (90 V )  /  (1.25 A)  =  72 ohms .

The resistance changed between situation-1 and situation-2 .
How did that happen ?

Power = (voltage) x (current)

Power-1 = (12)  x  (0.185)  =  2.22 watts

Power-2 = (90)  x  (1.25)  =  112.5 watts

The poor resistor dissipated 51 times as much power during
the second trial.  It got all heated up, and its resistance went
through the roof.

Carbon resistors behave nicely and reliably, until you try to
toast bread or light up your bedroom with them.


8 0
3 years ago
A golf ball is dropped from rest from a height of 9.5m.  It hits the pavement then bounces back up rising  just 5.7 m before fal
Oksanka [162]

Answer: 3.4s

Explanation:

There are three stages in the motion of the ball, so you have to calculate the times for every stage.

1) Ball dropping from 9.5m: free fall

d = Vo + gt² / 2

Vo = 0 ⇒ d = gt² / 2 ⇒ t² = 2d / g = 2 × 9.5 m / 9.81 m/s² = 1.94 s²

⇒ t = √ (1.94 s²) = 1.39s

2) Ball rising 5.7m (vertical rise)

i) Determine the initial speed:

Vf² = Vo² - 2gd

Vf² = 0 ⇒ Vo² = 2gd = 2 × 9.81 m/s² × 5.7m = 111.8 m²/s²

⇒ Vo = 10.6 m/s

ii) time rising

Vf = Vo - gt

Vf = 0 ⇒ Vo = gt ⇒

t = Vo / g = 10.6 m/s / 9.81 m/s² = 1.08 s

3) Ball dropping from 5.7 m to 1.20m above the pavement (free fall)

i) d = 5.7m - 1.20m = 4.5m

ii) d = gt² / 2 ⇒ t² = 2d / g = 2 × 4.5 m / 9.81 m/s² = 0.92 s²

⇒ t = √ (0.92 s²) = 0.96s

4) Total time

t = 1.39s + 1.08s + 0.96s = 3.43s ≈ 3.4s

4 0
3 years ago
Read 2 more answers
An object is observed for a time interval of 20 seconds. From time 6.7 s the object experiences a Force of 106 N that lasts unti
shusha [124]

Answer:

1654 kg m/s

Explanation:

The impulse experienced by an object is equal to the product between the force exerted on the object and the time during which the force lasts:

I=F\Delta t

where:

I is the impulse

F is the force exerted on the object

\Delta t is the time during which the force is applied

For the object in this problem, we have

F=106 N (force applied)

\Delta t= 15.6 s (time interval)

Therefore, the impulse experienced by the object is:

I=(106)(15.6)=1654 kg m/s

3 0
3 years ago
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