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Natasha_Volkova [10]

4 years ago

9

What is the initial value of y in the equation y=2(2.71)^x

1 answer:

eimsori [14]4 years ago

6 0

We have the following equation:
y = 2 (2.71) ^ x
It is an equation of the form:
y = A (b) ^ x
Where,
A: initial amount
b: growth rate
We have then that the initial amount occurs for x = 0
Substituting:
y = 2 (2.71) ^ 0
y = 2 (1)
y = 2
Answer:
the initial value of and in the equation y = 2 (2.71) ^ x is:
y = 2

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Answer:

41.5 units

Step-by-step explanation:

Given the data :

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3 years ago

The point P(8, −3) lies on the curve y = 3/(7 − x). (a) If Q is the point (x, 3/(7 − x)), use your calculator to find the slope

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Answer:

Slope of the line $PQ is -63.434948.$

Step-by-step explanation:

Given that,

The point $P(8,-3)$ lies on the curve $y=\frac{3}{7-x}$ .

If $Q$ is the point lies on $(x,\frac{3}{7-x} )$ .

To find:- Find the slope of line $PQ$ .

So,

The coordinates of point $Q$ when it lies on $(x,\frac{3}{7-x} )$

if $x=1$ then $y= \frac{3}{7-1} =\frac{3}{6} =\frac{1}{2}$

So, $Q$ ≡ $(1,\frac{1}{2} )$ and many points can be calculated by given Equation.

Using the formula when two points $(x_{1} ,y_{1} ) \& (x_{2}, y_{2} )$ .

$Slope=Tan\theta = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Then, substituting the coordinates we get,

$Slope = \frac{1-8}{\frac{1}{2}-(-3) }$

$Slope = \frac{-7}{\frac{1}{2}+3 } = \frac{-7}{\frac{7}{2} }$

$Slope = \frac{-14}{7}=-2$

$tan\theta=-2$ ⇒ $\theta = tan^{-1} (-2)$

$\theta= -63.434948$

Therefore,

Slope of the line $mPQ is -63.434948.$

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