Interpreting the graph and the situation, it is found that the values of d that can be included in the solution set are 1 and 4.
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- According to Benford's law, the probability of a number starting with digit is d is:
![P(d) = \log{(d + 1}} - \log{d}](https://tex.z-dn.net/?f=P%28d%29%20%3D%20%5Clog%7B%28d%20%2B%201%7D%7D%20-%20%5Clog%7Bd%7D)
- A number can start with 10 possible digits, ranging from 1 to 9, which are all integer digits.
- Thus, d can only assume integer digits.
- In the graph, the solution is d < 5.
- The integer options for values of d are 1 and 4.
- For the other options that are less than 5, they are not integers, so d cannot assume those values.
A similar problem is given at brainly.com/question/16764162
Answer:
Domain (0, ∞) and Range (-∞, ∞).
Step-by-step explanation:
The domain of f(x) = 0.5^x is all values of x and the range is f(x)>0 as 0.5^x cannot be negative or zero.
In interval form this is Domain is (-∞, ∞) and Range is (0, ∞).
So its inverse has Domain (0, ∞) and Range (-∞, ∞).
The anwser is 5.05 cm hahahahahahahahahahahahah
Assuming that the given shape is a cuboid,
volume=l×w×h
v=s³ (since cuboids have same length, they have same side length)
62=s³
∛62=s
s=3.957 ≈ 4 units
Hope I helped :)
First we need to find out the time it took for the truck to reach town B.
![Speed= \frac{Distance}{Time}](https://tex.z-dn.net/?f=Speed%3D%20%5Cfrac%7BDistance%7D%7BTime%7D)
![40= \frac{200}{T}](https://tex.z-dn.net/?f=40%3D%20%5Cfrac%7B200%7D%7BT%7D%20)
![T=5hours](https://tex.z-dn.net/?f=T%3D5hours)
Now, because the van left 1.5 hours earlier and reached the destination 2.5 hours before, it took 1 hour less the the truck to arrive.
![5hours-1hour=4hours](https://tex.z-dn.net/?f=5hours-1hour%3D4hours)
which is the time it took for the van to arrive.
Now we use the speed equation again to work out speed.
![Speed= \frac{200}{4}](https://tex.z-dn.net/?f=Speed%3D%20%5Cfrac%7B200%7D%7B4%7D%20)
![Speed=50mph](https://tex.z-dn.net/?f=Speed%3D50mph)
= speed of van
Hope this helped :)