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Gre4nikov [31]
3 years ago
5

ATCs are required to undergo periodic random drug testing.

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0

Answer:

The responsess to the given question can be defined as follows:

Step-by-step explanation:

P(medication\ used) = 0.007 \\\\P( drug \not\ used ) = 1 - 0.007 = 0.993\\\\P(test\ positive  | medication \ used) = 0.96 \\\\ P(test \ negative | medication \ used) = 1 - 0.96 = 0.04\\\\

P(Point | Non-used\ medication )=0.93\\\\ P(Point |No\ medication ) = 1 - 0.93 = 0.07

As per the given info we draw the tree diagram which is defined in the attachment file.

P ( test \ is\  positive ) = P( medication \ used ) \times P( Test \ positive | medication \ used ) + P( medication not \ used ) \times  P( Test\ positive | medication \ not \ used )

                  = ( 0.007 \times 0.96 ) + ( 0.993\times 0.07 )\\\\= 0.0762

P( medication \ used | test\ positive )= \frac{\textup{P( medication used ) *P( Test positive given medication  used )}}{\textup{P( medication used )}}  

= \frac{( 0.007\times 0.96 )}{0.0762}\\\\= 0.0882

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Genrish500 [490]

Answer:

The surface area of the gift box is = A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}

Step-by-step explanation:

The surface area of the cylinder can be calculated using this formula:

A=2\pi rh+2\pi r^2

in this case, r is not a number, but rather an expression, which is r = 3x +1.

The height of the gift box is twice the radius, which is h = 2(3x+1)= 6x+2

To get our curved surface area, we carefully put the expressions for h and r into the equation.

A = 2 \times \frac{22}{7} \times (3x+1) \times (6x+2) + 2 \times \frac{22}{7} \times (3x+1)^{2}

A = \frac{44}{7} (3x+1) \times (6x +2) + \frac{44}{7} (9x^{2} + 6x +1)\\A =\frac{132}{7}x + \frac{44}{7} \times (6x+2)+ \frac{396}{7}x^{2}+\frac{246}{7}x +\frac{44}{7}

A = \frac{792}{7}x^{2} +\frac{264}{7}x +\frac{264}{7}x + \frac{88}{7} + \frac{396}{7}x^{2} + \frac{246}{7}x + \frac{44}{7}

A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}

The surface area of the gift box is = A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}

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4 years ago
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