We know that
<span>the regular hexagon can be divided into 6 equilateral triangles
</span>
area of one equilateral triangle=s²*√3/4
for s=3 in
area of one equilateral triangle=9*√3/4 in²
area of a circle=pi*r²
in this problem the radius is equal to the side of a regular hexagon
r=3 in
area of the circle=pi*3²-----> 9*pi in²
we divide that area into 6 equal parts------> 9*pi/6----> 3*pi/2 in²
the area of a segment formed by a side of the hexagon and the circle is equal to <span>1/6 of the area of the circle minus the area of 1 equilateral triangle
</span>so
[ (3/2)*pi in²-(9/4)*√3 in²]
the answer is
[ (3/2)*pi in²-(9/4)*√3 in²]
Answer:
Parallel: G and F
perpendicular: G & H, F & H
Step-by-step explanation:
G and F are parallel because they will never cross, where as both are perpendicular to H because they intersect at 90°
11/15-2/5
Multiply 2 and 5 to get a common denominator of 15
11/15-6/15
=4/15
Answer:
The second choice
Step-by-step explanation:
