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Mkey [24]
3 years ago
7

How many hours would someone who earns $7.50 per hour have to work to earn $116.25?

Mathematics
2 answers:
Goshia [24]3 years ago
5 0
Here is your answer:

Need to divide the amount he wants to the amount he gets every hour:

116.25÷7.50=15.5 hours

Which mean he has to work 15 and a half hours

Your answer is...
15.5 or if rounded 16 hours! Hope this Helps!
ser-zykov [4K]3 years ago
4 0
If taks are not an issue the person would have to work 15.5 hours to earn $116.25
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An automobile manufacturer who wishes to advertise that one of its models achieves 30 mpg (miles per gallon) decides to carry ou
Katyanochek1 [597]

Answer:

t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17  

p_v =P(t_{(5)}  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.  

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

Step-by-step explanation:

Data given and notation  

The mean and sample deviation can be calculated from the following formulas:

\bar X =\frac{\sum_{i=1}^n x_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)}{n-1}}

\bar X=29.35 represent the sample mean  

s=1.365 represent the sample standard deviation  

n=6 sample size  

\mu_o =30 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is lower than 30 or no, the system of hypothesis are :  

Null hypothesis:\mu \geq 30  

Alternative hypothesis:\mu < 30  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17  

P-value  

We need to calculate the degrees of freedom first given by:  

df=n-1=6-1=5  

Since is a one-side left tailed test the p value would given by:  

p_v =P(t_{(5)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.  

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

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3 years ago
Which of the following statements is not correct?
NeX [460]

Answer:

The highest percentage of teenagers in the sample

listed soccer as their favorite sport.

Basketball

Lacrosse

Soccer

Football

Step-by-step explanation:

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3 years ago
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Find the slope of the line that passes through (-11, 75) and (27, -9).
Marrrta [24]

Answer:

\frac{y__2-y__1}{x__2-x__1}

y = -9 + 75 = 66

x = 27-(-11) = 27 + 11 = 38

slope = 66/28

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Galina-37 [17]

Answer:

Step-by-step explanation:

Suppose the base formula is y = x^2

You want to go two units left.

basically that is y = (x + 2)^2 just the opposite of what you might think it should be.

Where does the base function have a minimum? It's minimum is as x = 0 and y = 0

Where does y = (x + 2)^2 have it's minimum?

(-2,0)

conclusion. The base function has moved 2 units to the left.

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3 years ago
What is the measurement of angle BEC?
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Answer:

I think its -120 but am not sure so sorry if its wrong

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