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Serga [27]
3 years ago
11

Assume that x and y are boolean variables and have been properly initialized.(x && y) || !(x && y) The result of

evaluating the expression above is best described as (A) always true (B) always false (C) true only when x is true and y is true (D) true only when x and y have the same value (E) true only when x and y have different values
Computers and Technology
1 answer:
klemol [59]3 years ago
6 0

Answer:

(A) Always true

<em></em>

Explanation:

Given

Boolean variables x and y

Required

What is (x && y) || !(x && y)

Irrespective of what x or y is, the x && y is always true

Take for instance:

<em>x = true;</em>

<em>y = true;</em>

<em>x&&y will also be true because the values of x and y were not altered</em>

<em />

<em>And this is true for whatever boolean value x or y assume</em>

<em />

Having said that:

x&&y = true

So, the expression is analysed as follows:

(x && y) || !(x && y)

Substitute true for x&&y

(true) || !(true)

<em>!(true) = false</em>

So, the expression becomes:

true || false

|| represents the OR operator; and it returns true if at least one of the conditions is true.

By this:

true || false = true

<em>Option (A) Always true </em><em>answers the question.</em>

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