D= # of dimes
q= # of quarters
QUANTITY EQUATION:
d + q= 64
COST EQUATION:
0.10d + 0.25q= $9.25
STEP 1:
multiply quantity equation by -0.10 to be able to eliminate the d term in step 2
(-0.10)(d + q)= (-0.10)(64)
-0.10d - 0.10q= -6.40
STEP 2:
add equation from step 1 to cost equation to eliminate the d term and solve for q
Add
0.10d + 0.25q= $9.25
-0.10d - 0.10q= -6.40
0.15q= 2.85
divide both sides by 0.15
q= 19 quarters
STEP 3:
substitute q value in step 2 into either original equation to find d value
d + q= 64
d + 19= 64
subtract 19 from both sides
d= 45 dimes
CHECK:
0.10d + 0.25q= $9.25
0.10(45) + 0.25(19)= 9.25
4.50 + 4.75= 9.25
9.25= 9.25
ANSWER: There are 45 dimes and 19 quarters.
Hope this helps! :)
Answer:
(y+1)^3
Step-by-step explanation:
When dividing powers, subtract them. Therefore, 5-2 = 3. So, (Y+1)^5/(Y+1)^2 = (Y+1)^3
Answer:
a) nothing and 30 dollars.
Step-by-step explanation:
Opportunity cost usually arises when faced with choices or alternatives such that one has to be chosen, while the other is forgone. The benefits forgone by choosing a certain option of the available choices is called opportunity cost.
Given that :
Option A requires $20 payment
Option B requires $50 payment
Opportunity cost of choosing A = nothing (since payment required for the other alternative is higher than the chosen option)
Opportunity cost of Choosing B = ($50 - $20) = $30 (By choosing option B over option A, $30 was forgone as the other option (option A requires $30 lesser payment)
