Since it is a parallelogram cente at point T,
then the measure of PT is equal to the measure of TR. And the measure of QT is
equal to the measure of TS.
PT = TR
a + 4 = 2a
4 = 2a -a
a = 4
PT = TR = 8 units
QT = TS
b = 2b -3
3 = 2b – b
b = 3
<span>QT = TS = 3 units</span>
Answer:
The area of the sector is 9.43 ft^2
Step-by-step explanation:
Here, we want to find the area of the sector with a central angle of 30 degrees
To do this, we use the formula below;
Area of sector = theta/360 * pi * r^2
theta = central angle = 30 degrees
r = radius = 6 ft
Thus, we have it that;
Area of sector = 30/360 * pi * 6^2
= 30/10 * pi = 3 * 3.142 = 9.43 ft^2
Find the mean of the first four test scores first.
(Add all numbers in set and divide by how many numbers there are)
81 + 87 + 71 + 89 = 328 / 4 = 82
Then, find the mean with the 85 added as the fifth term.
81 + 87 + 71 + 89 + 85 = 413 / 5 = 82.6
The impact that the 85 had on the mean test score was that the mean/average increased by 0.6.
Can you please complete your question
