Answer:
Step-by-step explanation:
f(x) = 1/4 x²+bx+10
the derivate is : f'(x) = 1/2 x +b
you have : f'(6)=0
1/2 (6)+b=0
3+b =0
b = -3
so f(x) = 1/4 x²-3x+10.......f(6) =1/4(6)² -3(6)+10 =9-18+10 =1
f(x) = 1/4(x-6)²+1... the vertex form
Answer:
![\left( fg\right) \left( x\right) =2x^3\sqrt[3]{x}\\\\\left( \frac{f}{g} \right) \left( x\right) =\frac{2x^{3}}{\sqrt[3]{x} }](https://tex.z-dn.net/?f=%5Cleft%28%20fg%5Cright%29%20%20%5Cleft%28%20x%5Cright%29%20%20%3D2x%5E3%5Csqrt%5B3%5D%7Bx%7D%5C%5C%5C%5C%5Cleft%28%20%5Cfrac%7Bf%7D%7Bg%7D%20%5Cright%29%20%20%5Cleft%28%20x%5Cright%29%20%20%3D%5Cfrac%7B2x%5E%7B3%7D%7D%7B%5Csqrt%5B3%5D%7Bx%7D%20%7D)
Step-by-step explanation:
Answer: 36π
Step-by-step explanation:
A = πr²
A = π(6)²
A = 36π
