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kogti [31]
2 years ago
13

Which rules define the function graphed below? Edge

Mathematics
1 answer:
valentina_108 [34]2 years ago
4 0

Answer:

B

Step-by-step explanation:

In the first part for every x, y is the value of x plus 2, while in the second part for every x. y is 5

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Can someone please help PLEASE
zhenek [66]
7, 9,11,13 odd integrates
4 0
3 years ago
If someone knows the answer please help
pickupchik [31]

The correct answer is D. D'(1, 5), E'(-1, 3), F'(-1, -4), G'(1, -2).

It's because of this: You need to calculate the distances, and they are in this case symmetric, so you look how far is from one side, and it will be the same on the other side. When you put it on graph, the coordinates are clear and the correct answer is D.

7 0
3 years ago
Customers of a phone company can choose between two service plans for long distance calls. The first plan has a $24 monthly fee
JulsSmile [24]

Answer:

600 minutes

Step-by-step explanation:

If we write both situations as an equation, we get:

y1 = 24 + 0.15x

<em>y1 </em><em>:</em><em> </em><em>total </em><em>cost </em><em>paid </em><em>in </em><em>first </em><em>plan</em>

<em>x </em><em>:</em><em> </em><em>total minutes </em><em>of </em><em>calls</em>

y2 = 0.19x

<em>y2 </em><em>:</em><em> </em><em>total </em><em>cost </em><em>in </em><em>second </em><em>plan</em>

<em>x:</em><em> </em><em>total </em><em>min</em><em>utes </em><em>of </em><em>call</em>

We are now looking for the situation where the total cost in the two plans is equal, so

y1 = y2

this gives

24 + 0.15x = 0.19x

<=> 0.04x = 24

<=> x = 600

7 0
3 years ago
Solve the equation for h? X=r-h/y
Troyanec [42]

Answer:

h = yX -yr

Step-by-step explanation:

X=r-h/y

X - r = h/y

y*(X-r) = h

h = yX -yr

4 0
3 years ago
What are the roots of the polynomial equation 3x^4+12x^2=6x^3
Dominik [7]
Factor the equation to give
3x^4+12x^2=6x^3
3x^4+12x^2-6x^3=0
x^2(3x^2+12-6x)=0
By the zero product property, either x^2=0 or (3x^2+12-6x)=0 or both.
If x^2=0, then x=0
if (3x^2+12-6x)=0, we use the quadratic formula to solve for x
where x=1 &pm; &radic; (3) i

Answer: the roots of <span>3x^4+12x^2=6x^3 are {0 (multiplicity 2), 1+&radic;3 i, 1-&radic;3 i}</span>
7 0
3 years ago
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