Answer:
option A.
Step-by-step explanation:
To solve this, we need to use the following exponent rules:
Quotient rule: (a^n)/(a^m) = a^(n-m)
Power rule: (a^n)^m = a^nm
Power of a product rule: (ab)^n = (a^n)(b^n)
Then, we have the following expressions:
![[\frac{a^{-8}b}{a^{-5} b^{3}}}]^{-3}=[a^{-8+5}b^{1-3}}}]^{-3}=[a^{-3}b^{-2}]^{-3} =a^{9}b^{6}](https://tex.z-dn.net/?f=%5B%5Cfrac%7Ba%5E%7B-8%7Db%7D%7Ba%5E%7B-5%7D%20b%5E%7B3%7D%7D%7D%5D%5E%7B-3%7D%3D%5Ba%5E%7B-8%2B5%7Db%5E%7B1-3%7D%7D%7D%5D%5E%7B-3%7D%3D%5Ba%5E%7B-3%7Db%5E%7B-2%7D%5D%5E%7B-3%7D%20%3Da%5E%7B9%7Db%5E%7B6%7D)
So the correct result is option A.
Answer:
No, the opposite would be negative 6/4
Step-by-step explanation:
3/2 is just a simplified version of 6/4
The 3 is in the tens place, meaning the value of the 3 is 3x10.
The 9 is in the ones place, meaning the value of the 9 is 9x1
So the place value of the 3 is ten times the value of the place value of the 9.
Answer:
we need the data to answer your question
Step-by-step explanation:
