Answer:
The answer is "Option A"
Explanation:
Escalation is the process of manipulating a bug, design failure in software program to obtain elevated access to the resources, which are usually shielded from the user, and wrong choices can be described as follows:
- In option B, It is wrong because It can't provide any type of problem-solving.
- In option C, It is wrong because it is a searching module.
- In option D, It is wrong because it is used to verify the system.
Answer:
The correct answer to the following question will be "Product".
Explanation:
- Product marketing is often a mechanism by which a brand is marketed and delivered to a client. It's also known as the intermediate feature between product innovation and brand recognition or awareness.
- It's something to which comparison is made when selling a product on the market to the consumer.
Therefore, the Product is the right answer for the above question.
It’s real my easy you can use a calculator or an online converter. Or division
(111001)₂ = (1 × 2⁵) + (1 × 2⁴) + (1 × 2³) + (0 × 2²) + (0 × 2¹) + (1 × 2⁰) = (57)₁₀
(1100000)₂ = (1 × 2⁶) + (1 × 2⁵) + (0 × 2⁴) + (0 × 2³) + (0 × 2²) + (0 × 2¹) + (0 × 2⁰) = (96)₁₀
(1010101)₂ = (1 × 2⁶) + (0 × 2⁵) + (1 × 2⁴) + (0 × 2³) + (1 × 2²) + (0 × 2¹) + (1 × 2⁰) = (85)₁₀
(1001000)₂ = (1 × 2⁶) + (0 × 2⁵) + (0 × 2⁴) + (1 × 2³) + (0 × 2²) + (0 × 2¹) + (0 × 2⁰) = (72)₁₀
Answer:
// here is code in c++ to find the approx value of "e".
#include <bits/stdc++.h>
using namespace std;
// function to find factorial of a number
double fact(int n){
double f =1.0;
// if n=0 then return 1
if(n==0)
return 1;
for(int a=1;a<=n;++a)
f = f *a;
// return the factorial of number
return f;
}
// driver function
int main()
{
// variable
int n;
double sum=0;
cout<<"enter n:";
// read the value of n
cin>>n;
// Calculate the sum of the series
for (int x = 0; x <= n; x++)
{
sum += 1.0/fact(x);
}
// print the approx value of "e"
cout<<"Approx Value of e is: "<<sum<<endl;
return 0;
}
Explanation:
Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".
Output:
enter n:12
Approx Value of e is: 2.71828
Answer:
<h3>
<em><u>C</u></em><em><u>.</u></em><em><u> </u></em><em><u> </u></em><em><u>City</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>state</u></em><em><u> </u></em><em><u>where</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>was</u></em><em><u> </u></em><em><u>published</u></em></h3>
Explanation:
<h3>#CarryOnLearning</h3>
