It was not. Movies then talking movies were before television.
True they can pretty much see anything you do and on top of that they can look through your cameras. thats why i keep tape on my camera on my laptop
Answer:
to give us correct information.
i think
Answer:
Here is the code for a classic C++ program that does it:
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#include <iostream>
using namespace std;
int main()
{
int sum = 0;
int n;
cout << "Input 10 numbers: " << endl;
for (int i = 0; i < 10; i++)
{
cin >> n;
sum += n;
}
cout << "Sum of the numbers: " << sum << endl;
}
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Explanation:
I'm assuming you know what "include", "using namespace std" and "int main()" do, so I will skip over those.
First, we declare a variable "sum" and initialize it with 0 so we can add numbers to it later.
Then, we declare a variable "n" that will be set as the input of the user.
The "for-loop" will iterate ( go ) from 0 to 9, and will set the value of "n" as the input that is given -> "cin >> n;". After that, we add the value of "n" to the sum variable.
After "i" reaches 9, it will exit the loop and proceed to printing the sum of the numbers.
Hope it helped!
Answer:
C. 22
Explanation:
Given that the argument is being passed by value, there is no memory to consider. So cookieJar(7) returns 7 and cookieJar(22) returns 22.
If the argument parameter was passed by reference or pointer, then perhaps the value from cookieJar(7) would be considered with cookieJar(22).
Note, this code block really isn't doing anything other than returning the value passed into it. The "amount" variable is immediately set to 0, and then the value passed in is added to amount (which is 0), and returns. The following code could replace this function:
public static int cookieJar(int addCookies){
return addCookies;
}
The above code will return an equivalent output to the given code.
Notice, the function is not dependent on any previous call, so the value for each is unique to the call itself, i.e., cookieJar(22) returns 22 and cookieJar(7) returns 7.
So, C. 22 would be correct.
