The y-coordinate of point j' in the image triangle J'K'L' is -x coordinate of point j in the initial triangle JKL.
Step-by-step explanation:
The rule to apply here is that of 90° clockwise about the origin.
This is to say that: rotation 270° counterclockwise about the origin applies the same rule as rotation 90° clockwise about the origin.
In this case, If point j has coordinates (x,y) then after the rotation j' will have coordinates (y,-x)
So the y-coordinate of point j' in the image triangle J'K'L' is -x coordinate of point j in the initial triangle JKL.
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Rotation about the origin 270°:brainly.com/question/3382538
Keywords : triangle, rotated, origin, counterclockwise,y-coordinate
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Answer:
20+4x=10+2x
Step-by-step explanation:
Answer:
(x+5)^2 = 1
Step-by-step explanation:
x^2+10x+24 = 0
Subtract 24 from each side
x^2+10x+24 -24 = 0-24
x^2+10x = -24
Take the coefficient of x
10
Divide by 2
10/2 =5
Square it
5^2 = 25
Add it to each side
x^2+10x+25 = -24+25
Take the coefficient divided by 2 inside the factor
(x+10/2) ^2 = -24+25
(x+5)^2 = 1
Answer:
<h2>15°</h2>
Step-by-step explanation:
We know that the central angle of a circle is 360°.
In this case, we have the circle divided into 12 equal parts, so each angle would be also the 12th part of 360°.
Each circular sector has an angle of 30°, and each arc is equal to 30°.
Now, notice that tha angle formed by the two blue cables is an external angle formed by two secants, that means we can use the following relation
Where 
is the angle formed by the two blue cables.
Therefore, the angle measures 15°.
