Answer:
$28,800
Explanation:
I will just assume that there are three equal annual principal payments of $480,000. If we use $550,000, the total principal would = $1,650,000.
accrued interests from September to December = principal x (9%/12) x 4 months
principal = $480,000 x 2 = $960,000
accrued interest payable = $960,000 x 0.75% x 4 = $28,800
Answer:
Explanation:
Let's first determine the free cash flow of the firm
Particulars Years
1 2 3
EBIT 540 680 750
<u>Tax at 36% (0.36*540) (0.36*680) (0.36*750) </u>
Less: 345.6 435.2 480
Net Capital -
Spending 150 170 190
<u>Change in NWC 70 75 80 </u>
Less: 125.6 190.2 210
The terminal value at the end of T =(3 years) is:
![= \dfrac{Free \ cash \ flow}{unlevered \ cost - expected \ growth \ rate}](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7BFree%20%5C%20cash%20%5C%20flow%7D%7Bunlevered%20%5C%20cost%20-%20expected%20%5C%20growth%20%20%5C%20rate%7D)
![= \dfrac{250}{0.1643-0.04}](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7B250%7D%7B0.1643-0.04%7D)
![= \dfrac{250}{0.1243}](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7B250%7D%7B0.1243%7D)
= 2011.26
Finally, the value of the firm can be computed as follows:
Years Free Cash Flow PVIF PV
1 125.6 0.6589 107.88
2 190.2 0.7377 140.31
3 210 0.6336 133.06
<u>Terminal Value 2011.26 0.6336 1294.33 </u>
<u>Value of the firm ⇒ $1655.58</u>
Answer: The correct answer is "d. all of the above"
Explanation: In a perfectly-competitive industry a firm have no incentive to enter or exit the industry when:
- market price is equal to minimum long-run average cost.
- each firm earns a normal return.
This happens because in perfect competition companies reach a long-term equilibrium where extraordinary benefits are eliminated.
Answer:
The correct answer is A. $18,276
Explanation:
First you have to calculate how much you'd end up having at the end of the 25 years period in your savings account.
You calculate the total amount saved for each year, using the formula:
![S_{n} = S_{n-1} *(1+r)+D](https://tex.z-dn.net/?f=S_%7Bn%7D%20%3D%20S_%7Bn-1%7D%20%2A%281%2Br%29%2BD)
Where
is the total amount in the savings account for this period.
is the total amount in the savings account from the previous period.
is the interest rate.
are the annual deposits being made into the savings account.
Therefore for the first year you'd do:
![S_{1} = S_{0} *(1+r)+D](https://tex.z-dn.net/?f=S_%7B1%7D%20%3D%20S_%7B0%7D%20%2A%281%2Br%29%2BD)
![S_{1} = 0*(1+0.08)+5000=5000](https://tex.z-dn.net/?f=S_%7B1%7D%20%3D%200%2A%281%2B0.08%29%2B5000%3D5000)
For the second year:
![S_{2} = S_{1} *(1+r)+D](https://tex.z-dn.net/?f=S_%7B2%7D%20%3D%20S_%7B1%7D%20%2A%281%2Br%29%2BD)
![S_{2} = 5000*(1+0.08)+5000=10400](https://tex.z-dn.net/?f=S_%7B2%7D%20%3D%205000%2A%281%2B0.08%29%2B5000%3D10400)
And so on. You can help yourself calculate the value of this series using programs like Excel.
I have attached an Excel file that has a table with the savings values for each of the 25 years.
So, the 25th year you’ll have $365,529.70 in your savings account. Now you simply divide this number by 20 (that will be the number of years you’ll be withdrawing the same dollar amount from your savings account):
![Withdrawals = 365,529.70/20=18,276.485](https://tex.z-dn.net/?f=Withdrawals%20%3D%20365%2C529.70%2F20%3D18%2C276.485)
In conclusion, you’d be able to withdraw $18,276.485 each year for the following 20 years after the 25th deposit, if all withdrawals are the same dollar amount.