All categories

3 years ago

PLEASE HELP ME!!! PLEASE

Mathematics

2 answers:

SpyIntel [72]3 years ago

8 0

(8,-7) I think! Hope this helps!

Hoochie [10]3 years ago

7 0

Answer:

it should be (8,-7)

Step-by-step explanation:

You might be interested in

suppose a triangle has two sides of length 42 and 35 and that the angle.between these two sides is 120° what is the length of th

pickupchik [31]

Answer:

The length of the third side of the triangle is $7\sqrt{91}\ units$

Step-by-step explanation:

Let

c ----> the length of the third side of the triangle

we know that

Applying the law of cosines

$c^2=a^2+b^2-2(a)(b)cos(C)$

we have

$a=42\ units\\b=35\ units\\C=120^o$

substitute the given values

$c^2=42^2+35^2-2(42)(35)cos(120^o)$

$c^2=2,989-2,940cos(120^o)$

$c^2=4,459\\c=\sqrt{4,459}\ units\\c=7\sqrt{91}\ units$

6 0

3 years ago

- 2 root 2 + root 2 ?

KonstantinChe [14]

The answer is -root 2

Mark as brainliest plz.

8 0

3 years ago

PLS HELP Anna buys bananas and apples. She buys 2 more apples than twice the number

Alecsey [184]

Answer:

You have to put this in a bar model yourself so convert it later

She bought 10 apples

Step-by-step explanation:

3x + 2 = 14

why i did this

because she bought 2 times the amount of bananas, it should be x + 2x = 3x

then i added two because she bought two extra apples

so 3x+2 = 14

subtract 2

3x = 12

x = 4

So now we substitute x in apples

2x +2 = # of apples

8 +2 = 10

check

10 - 2 = 8

8/2 = 4

4 = # of bananas

4 0

3 years ago

Read 2 more answers

In April, Phillipa rode 13 . 5 + 8 . 7 + 11 . 1 miles on her bicycle. In March, she rode ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 miles,

bonufazy [111]

Answer:

Phillipa rode the most in May and rode the least in March.

Distance travelled by Phillipa on her cycle in May = 8 × Distance travelled by Phillipa on her cycle in March

Step-by-step explanation:

Given:

In April, Phillipa rode 13 . 5 + 8 . 7 + 11 . 1 miles on her bicycle. In March, she rode ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 miles, and in May, she rode 4 × ( 13 . 5 + 8 . 7 + 11 . 1 ) miles.

To find: the month when she rode the most and the month when she rode the least

Solution:

Distance travelled by Phillipa on her cycle in April = 13 . 5 + 8 . 7 + 11 . 1 = 65 + 56 + 11 = 132 miles

Distance travelled by Phillipa on her cycle in March = ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 = $\frac{132}{2}=66$ miles

Distance travelled by Phillipa on her cycle in May = 4 × ( 13 . 5 + 8 . 7 + 11 . 1 ) = 4 × 132 = 528 miles

So, she rode the most in May and rode the least in March

Distance travelled by Phillipa on her cycle in May = 8 × Distance travelled by Phillipa on her cycle in March

8 0

3 years ago

Mr levels gave 5 tests the test scores were 200,225,215,199 and 225, what is the mean median and mode of the tests that mr level

allsm [11]

Answer:

median is 215

mode is 225

mean is 212.8

Step-by-step explanation:

Im pretty sure

3 0

3 years ago