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Natalija [7]
3 years ago
5

The polynomial p(x)=x^3-6x^2+32p(x)=x 3 −6x 2 +32p, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 6, x, squar

ed, plus, 32 has a known factor of (x-4)(x−4)left parenthesis, x, minus, 4, right parenthesis.
Mathematics
1 answer:
STatiana [176]3 years ago
7 0

Answer:

<h3>The remainder is zero</h3>

Step-by-step explanation:

Given the polynomial function p(x)=x^3-6x^2+32, if x-4 is a factor, then <u>we can find the remainder if the polynomial is divided by x -4.</u>

First we need to equate the function x - 4 to zero and find x;

x - 4 = 0

x= 0+4

x = 4

Next is to substitute x = 4 into the expression p(x)=x^3-6x^2+32

p(x)=x^3-6x^2+32

p(4)=(4)^3-6(4)^2+32

p(4) = 64 - 96 + 32

p(4) = 0

Hence the remainder when x-4 is divided by the polynomial is zero

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