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Arisa [49]
3 years ago
15

Find the value of x. round to the nearest tenth.

Mathematics
1 answer:
lozanna [386]3 years ago
5 0
The value of x is 29
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A rectangle is 12 feet long and 5 feet wide. If the length of the rectangle is increased by 25% and the width is decreased by 20
lisabon 2012 [21]

Answer:

30 square feet.

Step-by-step explanation:

We have to find the main area of the rectangle to determine the changes.

We know, Area of a rectangle = Length × Width

Given,

Length = 12 feet

Width = 5 feet

Therefore, the area of the rectangle = (12 × 5) Square feet.

The area of the rectangle = 60 square feet.

Now, if the length of the rectangle increased by 25%, the new length would be = 12 feet (12 feet × 25%) = 12 feet + 3 feet = 15 feet.

If the width increased by 20%, the latest width would be = 5 feet + (5 feet × 20%) = 5 feet + 1 foot = 6 feet.

The new area of that rectangle = (15 × 6) square feet = 90 square feet.

The changes of area from the previous rectangle is = (90 - 60) square feet = 30 square feet.

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A lawn darts team has choice of hitting a short field bonus throw or long zone bonus.
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Answer: i believe it is short field

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The groundskeeper of Estofer Park needs to mow 14,623 sq. ft. of grass, He can mow 13 sq. ft. of grass in one minute. How many m
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190,099 is your answer for the question
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A boat on the ocean is 2 mi from the nearest point on a straight? shoreline; that point is 15 mi from a restaurant on the shore.
Sladkaya [172]

Answer:

a) x  =  0,70 miles

T  =  1/2* (√4 + x²)  +( 15 - x )/3   Objective Function to minimize

b) V(min)  = 2.59 m/hr

Step-by-step explanation:

Let assume the boat is in Point A,  she lands in point B, and R  is the restaurant

Let call  x distance between the point O in  which perpendicular line from the boat get to shoreline, and the point were she land.

We know  distance is

d = v*t       ⇒  t = d/v

She rows at 2 miles/hr  and walk at 3 miles /hr

According to that she takes

c (hypotenuse) of right triangle  AOB/ 2 rowing

and  15 - x /3  walking

Total time is:

T  =  c/2  + ( 15-x )/3          c =√(2)² + x²     ⇒  T = [√(2)² + x²  ] /2  +  ( 15-x )/3  

T  =  1/2* (√4 + x²)  +( 15 - x )/3   (1)

And that is  the Objective function to minimize

a) Taking derivatives on both sides of the equation we get

T´(t)  =  x /( √4 + x²)  - 1/3    ⇒   T´(t)  = 0     x /( √4 + x²)  - 1/3 = 0

3*x - √( √4 + x²) = 0     ⇒  3*x  =  √( √4 + x²)

Squaring both sides

9x²  =  4 + x²     ⇒  8x²  = 4       x² = 1/2      x  =  0,70 miles

If we plug this value in the Objective function we will get the minimum time

1/2* (√4 + x²)  +( 15 - x )/3    ⇒ [√ 4  + 0,5] /2 +  14,3/3 = T (min)

T(min)  =  1.06 + 4.77  = 5.83 hr

Distance L (hypotenuse of right triangle AOR)

L = √(2)²  + (15)²   L  = 15,13 miles

And that distance have to be traveled at least in 5.83 hr rowing

Then  as  v = d/t      V(min)  =  15.13/ 5.83   ⇒    V(min)  = 2.59 m/hr

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The answer is e because the volume is 54 pi mm^3. This is because the volume of a cylinder is pi * r^2 * h. 
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