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Gnoma [55]
3 years ago
14

If A=i +j+2k B=2i+j+2k C=i-2j-2k Find the magnitude of (A+B+C)​

Mathematics
1 answer:
ss7ja [257]3 years ago
3 0

Answer: (6j-2j + 7k / 89

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10 to the power of 3 times what equals 630
vekshin1
10³ · x = 630
x = ?

10³ = 10 × 10 × 10 = 1,000

630 ÷ 1000 = x
630 ÷ 1000 = 0.63
x = 0.63

So we have:

10³ · 0.63 = 630
6 0
3 years ago
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Six times the difference of 6 and 4
marishachu [46]
It would be: 6 ( 6- 4)
= 6 ( 2)
= 12

So, Your Answer would be 12

Hope this helps!
8 0
3 years ago
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8x+20y=-120 as slope
Temka [501]

Answer:

y = -2/5x -6

slope is -2/5

y intercept -6

Step-by-step explanation:

8x+20y=-120

Slope intercept form is y = mx+b where m is the slope and b is the y intercept

Subtract 8x from each side

8x -8x+20y= -8x-120

20y = -8x - 120

Divide by 20

20y/20 = -8x/20 -120/20

y = -2/5x -6

3 0
3 years ago
A geometric series has second term 375 and fifth term 81 . find the sum to infinity of series .
Eduardwww [97]

Answer:  \bold{S_{\infty}=\dfrac{3125}{2}=1562.5}

<u>Step-by-step explanation:</u>

  a₁,  375,  a₃,   a₄,  81

First, let's find the ratio (r). There are three multiple from 375 to 81.

375r^3=81\\\\r^3=\dfrac{81}{375}\\\\\\r^3=\dfrac{27}{125}\qquad \leftarrow simplied\\\\\\\sqrt[3]{r^3} =\sqrt[3]{\dfrac{27}{125}}\\ \\\\r=\dfrac{3}{5}

Next, let's find a₁

a_1\bigg(\dfrac{3}{5}\bigg)=375\\\\\\a_1=375\bigg(\dfrac{5}{3}\bigg)\\\\\\a_1=125(5)\\\\\\a_1=625

Lastly, Use the Infinite Geometric Sum Formula to find the sum:

S_{\infty}=\dfrac{a_1}{1-r}\\\\\\.\quad =\dfrac{625}{1-\frac{3}{5}}\\\\\\.\quad =\dfrac{625}{\frac{2}{5}}\\\\\\.\quad = \dfrac{625(5)}{2}\\\\\\.\quad = \large\boxed{\dfrac{3125}{2}}

7 0
3 years ago
In triangle RPS, an exterior angle at R measures 64º, and Triangle?
Ira Lisetskai [31]

Step-by-step explanation:

Where is your question in order to answer it

5 0
3 years ago
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