![\frac{81040}{20}=4052](https://tex.z-dn.net/?f=%20%5Cfrac%7B81040%7D%7B20%7D%3D4052)
To check your work do 20 x 4052 which should equal the Original value that you are dividing
Answer: 4052
Answer:
![\frac{5}{96}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B96%7D)
Step-by-step explanation:
At the beginning, the jar contains the following beans:
5 purple
6 yellow
8 green
5 orange
Therefore, the total number of jellybeans in the jar tha beginning is:
![n=5+6+8+5=24](https://tex.z-dn.net/?f=n%3D5%2B6%2B8%2B5%3D24)
The number of yellow beans at the beginning is
![y=6](https://tex.z-dn.net/?f=y%3D6)
Therefore, the of selecting a yellow jellybean at the beginning is
![p(y)=\frac{y}{n}=\frac{6}{24}=\frac{1}{4}](https://tex.z-dn.net/?f=p%28y%29%3D%5Cfrac%7By%7D%7Bn%7D%3D%5Cfrac%7B6%7D%7B24%7D%3D%5Cfrac%7B1%7D%7B4%7D)
After selecting this yellow bean, the yellow bean it is replaced in the jar, so the number of total beans is still n = 24.
And the number of purple beans inside is
![p=5](https://tex.z-dn.net/?f=p%3D5)
So, the probability of selecting a purple bean at the 2nd attempt is
![p(p)=\frac{5}{24}](https://tex.z-dn.net/?f=p%28p%29%3D%5Cfrac%7B5%7D%7B24%7D)
Therefore, the combined probability of selecting a yellow jellybean followed by a purple one is
![p(yp)=p(y)\cdot p(p)=\frac{1}{4}\cdot \frac{5}{24}=\frac{5}{96}](https://tex.z-dn.net/?f=p%28yp%29%3Dp%28y%29%5Ccdot%20p%28p%29%3D%5Cfrac%7B1%7D%7B4%7D%5Ccdot%20%5Cfrac%7B5%7D%7B24%7D%3D%5Cfrac%7B5%7D%7B96%7D)
To do this, you have to know the original perimeter of this park (490 yds) and the area (14,500 yds squared)
A park with the same perimeter (490 yds) but smaller area (9,750 yds squared) is 195ydsx50yds
I am not sure I need help with same one
I should say that 13, 24, 14 are the next three numbers, because as you can see above the first(11) number is the third(12) number minus 1 and the fourth(23) is the second (22) plus 1 if you understand what I`m trying to say