Pretty sure it’s 4. Hope this helped :)
Answer: (x+2)*(x-4)*(x+21) = 0 has "many" solutions
Step-by-step explanation: (x+2) = 0 only has one solution.
(x+2)*(x-4) = 0 has two solutions, -2 and 4
(x+2)*(x-4)*(x+21) = 0 has three solutions, -2, 4, and -21, etc
If "many" means more than three, then add another (x+XX) term. A quadratic equation generally has two solutions.
