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2 years ago

What is the slope- intercept form of 3x-y=8

Mathematics

1 answer:

Art [367]2 years ago

3 0

Answer:

$y=3x-8$

Step-by-step explanation:

slope intercept form is $y=mx+b$ so just get the equation to look like this
$3x-y=8\\3x-(3x)-y=8-(3x)\\-y=-3x+8\\y=3x-8$

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Solve<br> 3x^2= 147<br> x=<br> X=

marin [14]

Answer:

$3 {x}^{2} = 147 \\ or \: x^{2} = \frac{147}{3} \\ or \: x = \sqrt{49} \\ x = 7$

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2 years ago

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un repartidor de refrescos entrego 90 cajas en tres pedidos. En le primero dejo el doble que en el segundo, y en el segundo, el

GenaCL600 [577]

Answer:

Step-by-step explanation:

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2 years ago

Solving systems of equations using substitution p=q+2<br> 4p+3q= -27

GREYUIT [131]

Ok, so you are given the value of P=q+2

The substitution method tells us that we must insert the value we know, into the second equation, 4P+3q= -27

Doing so will give us 4(q+2)+3q= -27

For right now, lets just focus on the first part, 4(q+2)

We can simplify this by distributing(multiplying) the 4 to whats inside the variables.

This will give us 4q+8

now lets add this back to the rest of the equation >>> 4q+8+3q = -27

We can further simplify by adding like terms >>> 7q+8 = -27

subtract the 8 from both sides >>> 7q = -35

now divide both sides by 7 >>> q = -35/7

Therefor q = -5

EDIT*

now that we know q = -5 we can put q into the equation for P !

we know that p=q+2

so lets put q in now >>> p=(-5)+2

and simplify>>> p = -3

I hope this helps:)

6 0

3 years ago

Which equation represents the polynomial function with zeros −1, 1, and 3 (multiplicity of 2), and a y-intercept of −18? (4 poin

Vlad [161]

Correct Answer:
3rd option is the correct answer

Solution:
The zeros of the polynomial are -1,1 and 3. The multiplicity of 3 is 2. So the polynomial can be expressed as:

$y=a (x-3)^{2}(x-1)(x+1)$

The y-intercept of the polynomial is -18. This means the polynomial passes through the point (0,-18). Therefore, y must be -18 when x = 0. Using these values of x and y in previous equation we get:

$-18=a (0-3)^{2}(0-1)(0+1) \\ \\ 
-18=-9a \\ \\ 
a=2$

The final equation of the polynomial becomes:

$y=2 (x-3)^{2}(x-1)(x+1)$

7 0

3 years ago

choose the point-slope form and f the equation below that represents the line through the point (6,-3) and has a slope of 1/2

AveGali [126]

Answer:

The point-slope form of this equation would be y + 3 = 1/2(x - 6)

Step-by-step explanation:

In order to find this, start with the base form of point-slope form.

y - y1 = m(x - x1)

Now input the slope for m and the point for (x1, y1)

y - -3 = 1/2(x - 6)

y + 3 = 1/2(x - 6)

6 0

3 years ago

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