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Dvinal [7]
3 years ago
7

Deni made $100 yesterday at work. His boss gave him $20 for showing up, and Deni makes $10 for every hour he works. How many hou

rs did Deni work?
HOW DO I SHOW MY WORK
Mathematics
2 answers:
Rina8888 [55]3 years ago
4 0

Answer:

write it out

Step-by-step explanation:

if he got 20 for showing up, you subtract to from the total right away, so now you have 80 total, and at a rate of 10/hr, he must have worked 8hrs. (80/10)

kompoz [17]3 years ago
4 0

Answer:

Deni worked 8 hours yesterday

Step-by-step explanation:

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3 years ago
A type of long-range radio transmits data across the Atlantic Ocean. The number of errors in the transmission during any given a
Marianna [84]

Answer:

32.33% probability of having at least 3 erros in an hour.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The mean number of errors is 2 per hour.

This means that \mu = 2

(a) What is the probability of having at least 3 errors in an hour?

Either you have 2 or less errors in an hour, or we have at least 3 errors. The sum of the probabilities of these events is decimal 1. So

P(X \leq 2) + P(X \geq 3) = 1

We want P(X \geq 3)

So

P(X \geq 3) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2}*(2)^{0}}{(0)!} = 0.1353

P(X = 1) = \frac{e^{-2}*(2)^{1}}{(1)!} = 0.2707

P(X = 2) = \frac{e^{-2}*(2)^{2}}{(2)!} = 0.2707

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P(X \geq 3) = 1 - P(X \leq 2) = 1 - 0.6767 = 0.3233

32.33% probability of having at least 3 erros in an hour.

6 0
3 years ago
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Step-by-step explanation:

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so Ax + (0)y = C

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3 years ago
34 + 2.5 =<br>(Input only whole numbers.)​
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Answer:

91

Step-by-step explanation:

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