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nika2105 [10]
4 years ago
11

Locating Zeros of Polynomial Function:Approximate the real zeros to the nearest tenth

Mathematics
1 answer:
solmaris [256]4 years ago
5 0

we are given

f(x)=2x^4-x^3+x-2

we can check each options

option-A:

-1,1

we can plug x=-1 and x=1 and check whethet f(x)=0

At x=-1:

f(-1)=2(-1)^4-(-1)^3+(-1)-2

f(-1)=0

At x=1:

f(1)=2(1)^4-(1)^3+(1)-2

f(1)=0

so, this is TRUE

option-B:

0,1

we can plug x=0 and x=1 and check whethet f(x)=0

At x=0:

f(0)=2(0)^4-(0)^3+(0)-2

f(0)=-2

At x=1:

f(1)=2(1)^4-(1)^3+(1)-2

f(1)=0

so, this is FALSE

option-C:

-2,-1

we can plug x=-2 and x=-1 and check whethet f(x)=0

At x=-2:

f(-2)=2(-2)^4-(-2)^3+(-2)-2

f(-2)=36

At x=-1:

f(-1)=2(-1)^4-(-1)^3+(-1)-2

f(-1)=0

so, this is FALSE

option-D:

-1,0

we can plug x=-1 and x=0 and check whethet f(x)=0

At x=-1:

f(-1)=2(-1)^4-(-1)^3+(-1)-2

f(-1)=0

At x=0:

f(0)=2(0)^4-(0)^3+(0)-2

f(0)=-2

so, this is FALSE



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The expression y = 4.998 · e^{1.098\cdot x} is the exponential function that passes through the points (- 1, 5 / 3) and (3, 135).

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Herein we find the location of two points set on Cartesian plane that belongs to an exponential function of the form:

y = A \cdot e^{B \cdot x}

Where:

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If we know that (x₁, y₁) = (- 1, 5 / 3) and (x₂, y₂) = (3, 135), then the following system of equations is generated:

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To learn more on exponential functions: brainly.com/question/11487261

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