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Oliga [24]
3 years ago
13

Select three ratios that are equivalent to 7: 6.

Mathematics
1 answer:
scZoUnD [109]3 years ago
5 0

Answer:

ratio number 1-  14:12

ratio number 2- 21:18

ratio number 3- 28:24

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You can know that 236 is a composite number because it is divisible by _____. A. 2 B. 3 C. 7 D. 6
kaheart [24]

A. 2

<h2>Explanation:</h2>

A composite number can be formed if you multiply two smaller positive integers. So the result is also a positive integer. Let's test each option:

Option A.

\frac{236}{2}=118 \\ \\ \\ So: \\ \\ 236=2\times 118

236 can be formed by multiplying two smaller positive integers that are 2 and 118.

Option B.

\frac{236}{3}=78.67 \ It's \ not \ an \ integer

Option c.

\frac{236}{7}=33.71 \ It's \ not \ an \ integer

Option d.

\frac{236}{7}=39.33 \ It's \ not \ an \ integer

<em>Only Option A meets the requirements.</em>

<h2>Learn more:</h2>

Inequalities: brainly.com/question/4600160

#LearnWithBrainly

3 0
3 years ago
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Suppose you are given a square with an inscribed circle. If the area of the square is 36 m^2. What is the area of the circle?
loris [4]
If the square has sides of 6 the circle has a radius of 3 so it's area is 9pi
4 0
3 years ago
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A4(3a2 - 2a + 1)<br> What’s the product
guajiro [1.7K]

The answer is

3a^6 - 2a^5 + a^4

6 0
3 years ago
Jammal spend $66 on supplies to make some woodworking items if he sells his items for $7.25 each how many items does he have to
inna [77]

Answer:

Step-by-step explanation:

5 0
3 years ago
According to a 2014 research study of national student engagement in the U.S., the average college student spends 17 hours per w
Nadusha1986 [10]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 17

For the alternative hypothesis,

µ < 17

This is a left tailed test.

Since the population standard deviation is not given, the distribution is a student's t.

Since n = 80,

Degrees of freedom, df = n - 1 = 80 - 1 = 79

t = (x - µ)/(s/√n)

Where

x = sample mean = 15.6

µ = population mean = 17

s = samples standard deviation = 4.5

t = (15.6 - 17)/(4.5/√80) = - 2.78

We would determine the p value using the t test calculator. It becomes

p = 0.0034

Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.

The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.

4 0
3 years ago
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