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worty [1.4K]
2 years ago
12

When is an algebraic expression in its lowest term​

Mathematics
1 answer:
Olegator [25]2 years ago
4 0
A rational expression has been reduced to lowest terms if all common factors from the numerator and denominator have been canceled. We already know how to do this with number fractions so let's take a quick look at an example.
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Please answer this question (picture)
ki77a [65]

3x + 4y is simplified


8 0
2 years ago
A school director must randomly select 6 teachers to part in a training session. There are 34 teachers at school. In how many di
prohojiy [21]

Answer:

Total possible ways to select 6 teachers from 34 teacher are ^{34}C_6=1344904.

Step-by-step explanation:

It is given that total number of teachers at a school is 34.

The school director must randomly select 6 teachers to part in a training session.

^nC_r=\frac{n!}{r!(n-r)!}

Where, n is total possible outcomes and r is number of selected outcomes.

Total teachers = 34

Selected teachers =6

Total number of possible ways to select 6 teachers from 34 teacher is

^{34}C_6=\frac{34!}{6!(34-6)!}

^{34}C_6=\frac{34\times 33\times 32\times 31\times 29\times 28!}{6!(28)!}

^{34}C_6=1344904

Therefore total possible ways to select 6 teachers from 34 teacher are ^{34}C_6=1344904.

7 0
2 years ago
Please helppp number 11
aivan3 [116]

Answer:

(1/3)⁷

Step-by-step explanation:

negative exponents work like this:

x⁻²=(1/x)²

Apply this theory to this equation:

3⁻⁷=

(1/3)⁷

4 0
3 years ago
Which ordered pair is a solution of the equation y = x - 2?
Liula [17]

Answer:

One order pair is  

( 2,0)

Step-by-step explanation:

What ordered pairs are the options?

Pick a value for  

x

and solve for  

y

. Or find the intercepts.

If  

x

=

2

, then:

y

=

2

−

2

⇒

y

=

0

So we have  

(

2

,

0

)

If  

x

=

0

, then:

y

=

0

−

2

⇒

y

=

−

2

Here we have  

(

0

,

−

2

)

You can simply use  

0

for both  

x

and  

y

(intercept) to get the same answer.

8 0
3 years ago
I need help with this question
Novay_Z [31]

Answer:

$ \frac{\sqrt{3} - 1}{2\sqrt{2}} $

$ \frac{-(\sqrt{3} + 1)}{2\sqrt{2}} $

$ - \frac{\sqrt{3} - 1}{\sqrt{3} + 1} $

Step-by-step explanation:

Given $ \frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6} $

(A) $ sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4}  + \frac{\pi}{6}) $

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$ sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2} $

$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}

(B) Cos(A + B) = CosAcosB - SinASinB

$ cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}}) $

$ \implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2} $

$ \implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}) $

$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}

(C) Tan(A + B) = $ \frac{Sin(A +B)}{Cos(A + B)} $

From the above obtained values this can be calculated and the value is $ - \frac{\sqrt{3} - 1}{\sqrt{3} + 1} $.

3 0
3 years ago
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