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atroni [7]
3 years ago
5

Plz help me will give brainlyest​

Mathematics
1 answer:
Roman55 [17]3 years ago
7 0

Answer:

20 flowers

Step-by-step explanation:

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Circle A’s circumference is 3 times the value of Circle B’s Area. Find Circle B’a radius.
Natali [406]

(side note: your formula C = 2πr^2 is incorrect, it should be C = 2πr)

Answer:

r = 9

Step-by-step explanation:

First let's find the circumference of Circle A. To use the formula we need radius. Since we have a diameter just divide by 2 to get radius. 27 / 2 = 13.5

Now plug that into C = 2πr: 2π*(13.5) = 27π

The question says that the area of circle B is 3x this value, so Circle B's area must be: 27π * 3 = 81π

Now plug that into A = πr^2 and solve for r:

81\pi=\pi r^{2}\\81=r^{2}\\\sqrt{81}=r\\9=r

(edited to correct a brain fart)

5 0
3 years ago
D= 2 - 6c <br> 1%2c - c = 1
omeli [17]
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3 0
3 years ago
(-5,-4) rotated 270° counterclockwise
stepladder [879]

Answer:

(4, - 5 )

Step-by-step explanation:

Under a counterclockwise rotation about the origin of 270°

a point (x, y ) → (- y, x ) , thus

(- 5, - 4 ) → (4, - 5 )

6 0
3 years ago
The scores on a placement test given to college freshmen for the past five years are approximately normally distributed with a me
Masteriza [31]

Answer:

And on this case we have a 0.0303% of chance that the sample variance would be higher than 20. So on this case its not reasonable that the sample variance would be higher than 20.

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

n=20 represent the sample size

s^2 =20 represent the sample variance obtained

\sigma^2 =8 represent the population variance

We can calculate the probability that S^2 would be higher than 20 and we will have an idea how to solve the problem.  

For this case we can use the following statistic:

\chi^2 =\frac{n-1}{\sigma^2} s^2

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

\chi^2 =\frac{20-1}{8} 20 =47.5

Calculate the probability

We can calculate the probability that S^2 would be higher than 20. The degrees of freedom are given by n-1=20-1=19

P(S^2 >20) =P(\chi^2_{19} >47.5)=0.000303

And hte reason of this is this one:

P(S^2 >20)= P(\frac{\chi^2 \sigma^2}{n-1}>20)=P(\chi^2 >\frac{20(n-1)}{\sigma^2})=P(\chi^2 >\frac{20*19}{8})=P(\chi^2 >47.5)

In order to calculate this probability we can use the following code in excel:

"==1-CHISQ.DIST(47.5,19,TRUE)"

And on this case we have a 0.0303% of chance that the sample variance would be higher than 20. So on this case its not reasonable that the sample variance would be higher than 20.

5 0
4 years ago
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