First, let's rearrange the given equation into something more recognizable. If we add 13 to both sides, we now have the polynomial $x^{2}-10x+13$ . We can now use the quadratic formula to solve.

Remember that the quadratic formula is

$\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}$

Substitute the numbers from the equation into the formula.

$\frac{-(-10)+/-\sqrt{(-10)^{2}-4(1)(13) } }{2(1)}$

Simplify:

$\frac{10+/-\sqrt{100-52} }{2}$

$\frac{10+/-\sqrt{48} }{2}$

Here, I'm going to assume that there was a mistype in option B because if we divide out the 2 we end up with $5+/-\sqrt{48}$ .

Hope this helps!

6 0

2 years ago

Find the value of x in each figure <br><br>

Ronch [10]

Answer:

X is 50

Step-by-step explanation:

3 0

2 years ago

How did you get these figures?

Serggg [28]

These figures?
well the most simple figures can be circle, triangle, square, etc... and you can write on how you got them.

5 0

2 years ago

What is the value of s?<br> units

liubo4ka [24]

Answer:

Is there any attachment?

Step-by-step explanation:

3 0

2 years ago

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