Which software application should be used when preparing a budget?
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The stress experimented by the bungee cord due to Max's weight is approximately 299.680 kilopascals.
<h3>How to find the stress experimented by the bungee cord</h3>
Let suppose that the stress (), in pascals, experimented by the bungee cord is entirely <em>elastic </em>and <em>uniform</em>. By Newton's Laws we know that the tension (
), in newtons, experimented by the cord equals Max's weight. The stress on the bungee cord is axial and is described by following formula:
(1)
Where:
- Max's mass, in kilograms
- Gravitational acceleration, in meters per square second
- Diameter of the circular cross section, in meters
If we know that ,
and
, then the stress experimented by the bungee cord is:
The stress experimented by the bungee cord due to Max's weight is approximately 299.680 kilopascals.
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Based on the calculations, the pressure inside this droplet is equal to 2,909.35 kPa.
<u>Given the following data:</u>
- Surface tension = 0.00518 lbf/ft to N/m = 0.00702 N/m.
- Atmospheric pressure = 14.7psia to kPa = 101.35 kPa.
- Diameter = 0.01 mm to m = 0.00001 m.
Radius, r = = 0.000005 m.
For a droplet with only one surface, its pressure is given by this formula:
Substituting the given parameters into the formula, we have;
Inside pressure = 2,909.35 kPa.
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