Answer:
-10
Step-by-step explanation:
-4 + -3 = -7
-7 + -2 = -9
-9 + -1 = -10
Answer:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
Step-by-step explanation:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
Answer:
The answer is 23.
Step-by-step explanation:
Our equation here is (2x + y) + 5.
If x=4, and y=10, let's plug that in into our variables, and simplify!
[2(4) + (10)] + 5
= [8+10] + 5
=[18] +5
=23
Answer: AB = 10.2
Explanation:
A(5.1, root11)
B(-5.1, root11)
AB = |5.1| + |-5.1| = 5.1 + 5.1 = 10.2
