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2 years ago

ASAP!!! I NEED HELP geometry/trigonometry please

Mathematics

1 answer:

777dan777 [17]2 years ago

6 0

Answer:

Perpendicular = Y = 34.64 ft (Approx)

Base = X = 20 ft

Step-by-step explanation:

Given:

θ = 60°

Hypotenuse = 40 ft

Perpendicular = Y

Base = X

Find:

X and Y

Computation:

Sinθ = Perpendicular / Hypotenuse

Sin 60 = Y / 40

Perpendicular = Y = 34.64 ft (Approx)

Cosθ = base / Hypotenuse

cos 60 = X / 40

Base = X = 20 ft

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sertanlavr [38]

Answer: the third one

Step-by-step explanation:

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2 years ago

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Can u guys plz give me ALL the following answers to graph 1.

creativ13 [48]

Slope ~3
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2 years ago

The object below was made by placing a cone on top of a cylinder. The base of the cone is congruent to the base of the cylinder.

Ber [7]

Answer:

Part 1) The volume of the object is $32\pi\ cm^{3}$ or $100.48\ cm^{3}$

Part 2) see the procedure

Step-by-step explanation:

The picture of the question in the attached figure

Part 1) What is the volume, in cubic centimeters, of the object?

we know that

The volume of the object is equal to the volume of the cylinder plus the volume of the cone

Find the volume of the cone

The volume of the cone is equal to

$V=\frac{1}{3}\pi r^{2} h$

we have

$r=4/2=2\ cm$ -----> the radius is half the diameter

$h=3\ cm$

substitute the values

$V=\frac{1}{3}\pi (2^{2})(3)=4\pi\ cm^{3}$

Find the volume of the cylinder

The volume of the cylinder is equal to

$V=\pi r^{2} h$

we have

$r=4/2=2\ cm$ -----> the radius is half the diameter

$h=(10-3)=7\ cm$

substitute the values

$V=\pi (2^{2})(7)=28\pi\ cm^{3}$

Part 2) Then explain how you found the volume of the total shape

The volume of the total shape is equal to the volume of the cylinder plus the volume of the cone

$4\pi\ cm^{3}+28\pi\ cm^{3}=32\pi\ cm^{3}$ ------> exact value

Find the approximate value of the volume

assume

$\pi=3.14$

$32(3.14)=100.48\ cm^{3}$

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2 years ago

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vovangra [49]

Answer:

11,199,081

Step-by-step explanation:

Hope this helped, have a great day! ;D

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2 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match the linear equations with their x-

jolli1 [7]

Answer:

Part 1) $x-2y=2$ ----> (2,0) and (0,-1)

Part 2) $-3x+3y=7$ ----> (-7/3,0) and (0,7/3)

Part 3) $7x-y=21$ ----> (3,0) and (0,-21)

Part 4) $3x-5y=-20$ ----> (-20/3,0) and (0,4)

Step-by-step explanation:

we know that

The y-intercept is the value of y when the value of x is equal to zero

The x-intercept is the value of x when the value of y is equal to zero

Part 1) we have

$x-2y=2$

1) Find the x-intercept

For y=0

$x-2(0)=2\\x=2$

the x-intercept is (2,0)

2) Find the y-intercept

For x=0

$0-2y=2\\y=-1$

the y-intercept is (0,-1)

Part 2) we have

$-3x+3y=7$

1) Find the x-intercept

For y=0

$-3x+3(0)=7\\x=-\frac{7}{3}$

the x-intercept is (-7/3,0)

2) Find the y-intercept

For x=0

$-3(0)+3y=7\\y=\frac{7}{3}$

the y-intercept is (0,7/3)

Part 3) we have

$7x-y=21$

1) Find the x-intercept

For y=0

$7x-(0)=21\\x=3$

the x-intercept is (3,0)

2) Find the y-intercept

For x=0

$7(0)-y=21\\y=-21$

the y-intercept is (0,-21)

Part 4) we have

$3x-5y=-20$

1) Find the x-intercept

For y=0

$3x-5(0)=-20\\x=-\frac{20}{3}$

the x-intercept is (-20/3,0)

2) Find the y-intercept

For x=0

$3(0)-5y=-20\\y=4$

the y-intercept is (0,4)

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3 years ago